3451 now I’m just putting 20 characters to answer lol
We know that
the law of sines establish
a/sin A=b/sin B
problem N 1
50/sin K=53/sin 76-------> 50*sin 76=53*sin K-----> sin K=50*sin 76/53
sin K=0.9154
K=arc sin (0.9154)--------> K=66.25°------> K=66°
the answer problem N 1 is the option
<span>c.) 66°
</span>
Problem N 2
30/sin R=35/sin 69------> sin R=30*sin 69/35-----> sin R=0.8002
R=arc sin(0.8002)-------> R=53.15°-----> R=53°
the answer problem N 2 is the option
<span>b.) 53°</span>
The perimeter = 4 * length of a semicircle of radius 5 == 4* pi * 5 = 20 pi cm
The area of one of the clear parts = 1/2 area of square - area semicircle
= 1/2 * 10^2 - 1/2 pi *5^2 = 50 - 12.5pi
So area of shaded parts = area of square - 4 (50 - 12.5pi)
= 100 - 200 + 100pi = (100pi - 100) cm^2
