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Talja [164]
3 years ago
9

What is 2+2.8/2.45*5.654=

Mathematics
2 answers:
bazaltina [42]3 years ago
8 0
By the order of operations, 8.4617
alekssr [168]3 years ago
6 0
8.4617....

Hope this helped you :)
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Convert to exponential form: log 1000=3
Luden [163]
\log_a b=c \hbox{ if } a^c=b \\ \\
\log 1000=3 \\
\log_{10} 1000=3 \\
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\boxed{10^3=1000}

8 0
3 years ago
2x + 9 = 83<br> HELP gOOD ANSWERS ONLY
mina [271]

Answer:

x = 37

Step-by-step explanation:

2x + 9 = 83

-9          -9

2x = 74

---    ----

2     2

x = 37

5 0
3 years ago
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In a race, the mean time for three runners was 12.4 seconds and the mean
Ne4ueva [31]

Answer:

11.8

Step-by-step explanation:

3(12.4) + 6(11.5) =  37.2 + 69 = 106.2

106.2/9 = 11.8

4 0
3 years ago
What is the x- intercept of y+ 12 =3 (x-9)?
Natalija [7]

Answer:

13,0

Step-by-step explanation:

12=3(x-9)

divide both sides by three

4=x-9

add 9 to both sides

x=13

so, the x intercept is (13,0)

7 0
2 years ago
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In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH
solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH   (*)

Consider triangles CBH and BCK. In these triangles,

  • ∠CBH ≅ ∠BCK (from equality (*));
  • ∠HCB ≅ ∠KBC, because m∠B = m∠C;
  • BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

5 0
3 years ago
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