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OverLord2011 [107]

2 years ago

14

If officer brimberry wrote 16 tickets for traffic violations last week but only 10 tickets this week what is the percent decreas

e

1 answer:

melamori03 [73]2 years ago

5 0

I believe this is right..

10/16= x/100
x=62.5%
100%- 62.5%= 37.5%

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Look at picture for problem

Jobisdone [24]

Add 2 3/4 and 2 1/2 and you’ll get ur answer. area means total and when u see area, it means add

8 0

2 years ago

13) (-2. – 5v).- (-4v – 2)<br> Can you help a girl out

irga5000 [103]

Answer:

If simplifed, it'll be -v

Step-by-step explanation:

8 0

2 years ago

Circles M and K are congruent, arc QR is congruent to arc LN and arc OP is congruent to arc VW. Find x.

SCORPION-xisa [38]

Given, arc QR is congruent to arc LN and arc OP is congruent to arc VW.

And the expressions for each arc in the diagram also given as:

Arc QR = 2x - y, arc LN = 11 , arc OP= 10 and arc VW=5x+y.

Hence, we will get the system of equations as following:

Arc QR = Arc LN

2x - y = 11 ...(1)

Arc OP = Arc VW

5x + y = 10 ...(2)

We need to find the value of x. So, we can add the equations to eliminate y so that we can solve the equations for x. Therefore,

2x+5x = 11 + 10

7x = 21

$\frac{7x}{7} =\frac{21}{7}$ Divide each sides by 7.

So, x= 3

6 0

3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

2 years ago

If 2a-b:2a+b=1:2find the value of a:b

weqwewe [10]

Answer & Step-by-step explanation:

2a - b : 2a + b = 1 : 2

2a - b = 1

- Elimination

2a + b = 2

-b - (b) = -1

-2b = -1

b = 0.5

---------------------------------------------------------------------------------

2a + b = 2 Substitution

2a + 0.5 = 2

2a = 1.5

a = 0.75

--------------------------------------------------------------------------------------

a:b

0.75 : 0.5

or

3/4 : 1/2

Hope this helps!!!

3 0

3 years ago