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3 years ago

Find the value of 2. A.126 B.121.5 C.117 D.63

Mathematics

1 answer:

Bezzdna [24]3 years ago

5 0

Answer:

Step-by-step explanation:

The tangent- tangent angle x is half the difference of the intercepted arcs.

The sum of the 2 arcs on the circle = 360°, thus

lower arc = 360° - 243° = 117°, then

x = $\frac{1}{2}$ (243 - 117)° = 0.5 × 126° = 63°

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What is the expanded form of the decimal 444.3? A) (4 x 100) + (4 x 10) + (4 x 1) + (3 x 1 10 ) B) (4 x 100) + (4 x 10) + (4 x 1

Tpy6a [65]

444.3 = (4 x 100) + (4 x 10) + (4 x 1) + (3 x 1 /10 )

Answer

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3 years ago

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3 years ago

Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .

Norma-Jean [14]

Answer:

y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

y = mx + b; where m is the slope and b is the y intercept

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$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1$

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

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The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

$y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11$

The equation of the perpendicular bisector is y = -x + 11

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3 years ago

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Y_Kistochka [10]

Step-by-step explanation:

It can answer your question

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2 years ago

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katovenus [111]

$\displaystyle\\
1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) = ? \\ \\ 
1 \frac{2}{5} = \frac{1\times 5+2}{5}=\boxed{\frac{7}{5}} \\ \\ 
-5 \frac{1}{2} =-5 -\frac{1}{2} = \frac{-5\times2-1}{2} =\frac{-10-1}{2}=\frac{-11}{2}= \boxed{-\frac{11}{2} }\\ \\ \texttt{OR} \\ \\ 
-5 \frac{1}{2} = -\Big(5 \frac{1}{2} \Big)= -\Big( \frac{5\times2+1}{2} \Big)=-\Big( \frac{11}{2} \Big)= \boxed{-\frac{11}{2} }$

$\displaystyle\\
\Longrightarrow ~~1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) =\frac{7}{5} -\frac{11}{2} = \frac{7\times 2}{5\times 2} -\frac{11\times 5}{2\times 5} = \\ \\ 
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