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Alenkinab [10]
3 years ago
15

Because a square is a rhombus it must have

Mathematics
1 answer:
RoseWind [281]3 years ago
4 0
Rhombuses have equal opposite sides, so in order for a square to be a rhombus, opposite sides must be equal. All squares are rhombuses. :)
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Kris’s mom is putting up a border on the walls of Kris’s room. Her room is 12 feet long and 10 feet wide. How much border will b
Oksanka [162]

Answer:

120 sq

Step-by-step explanation:

For example, if you are buying carpet for a room that is 12-feet long and 10-feet wide, multiply the two dimensions: 12 ft. x 10 ft. = 120 sq.

6 0
3 years ago
Rupees500 for 3years at 5 percent?​
Naya [18.7K]

What's the question?

6 0
3 years ago
Use sigma notation to represent the sum of a geometric series with a first term of 3 and a common ratio of . A. B. C. D.
maksim [4K]

Answer:

\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]

Step-by-step explanation:

A geometric sequence is a list of numbers having a common ratio. Each term after the first is gotten by multiplying the previous one by the common ratio.

The first term is denoted by a and the common ratio is denoted by r.

A geometric sequence has the form:

a, ar, ar², ar³, . . .

The nth term of a geometric sequence is ar^{n-1}

Therefore the sum of the first n terms is:

\Sigma_{k=1}^{n}(ar^{k-1})

Given a geometric series with a first term of 3 and a common ratio of 10/9, the sum of the first n terms is:

\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]

5 0
3 years ago
Garcia's Grill offers 77 side dishes, 55 types of steak, and 88 toppings. How many different smothered steak dinners can be made
svet-max [94.6K]

Answer:

Therefore the total number of ways that the customer can order the smothered steak dinner  is 9800.

Step-by-step explanation:

There are 7 side dishes, and  types of stake and 8 toppings.

The customer will have a smothered steak dinner.

The smothered steak dinner will consist of steak and 3 different toppings and 4\binom{8}{3} = \frac{8!}{3! \times 5!}  = 56 different side dishes.

The number of ways steak can be selected is =\binom{5}{1} = \frac{5!}{1! 4!}  =5

The number of ways toppings can be chosen is  = \binom{8}{3} = \frac{8!}{3! 5!}  = 56

The number of ways side dishes can be chosen = \binom{7}{4} = \frac{7!}{4!3!}  = 35.

Therefore the total number of ways that the customer can order the smothered steak dinner  is

= 5 × 56 × 35  = 9800.

7 0
3 years ago
6y+4−3y−7=3(y−1) How many solutions are for this?
Kryger [21]

Answer:

Infinite amount of solutions.

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Regular + Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

6y + 4 - 3y - 7 = 3(y - 1)

<u>Step 2: Solve for </u><em><u>y</u></em>

  1. Combine like terms:                         3y - 3 = 3(y - 1)
  2. Distribute 3:                                       3y - 3 = 3y - 3
  3. Subtract 3y on both sides:               -3 = -3

Here we see that there will be infinite amount of solutions. We can plug in any number <em>y</em> and it will render the equation true.

8 0
3 years ago
Read 2 more answers
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