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3 years ago

Because a square is a rhombus it must have

1 answer:

4 0

Rhombuses have equal opposite sides, so in order for a square to be a rhombus, opposite sides must be equal. All squares are rhombuses. :)

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Kris’s mom is putting up a border on the walls of Kris’s room. Her room is 12 feet long and 10 feet wide. How much border will b

Oksanka [162]

Answer:

120 sq

Step-by-step explanation:

For example, if you are buying carpet for a room that is 12-feet long and 10-feet wide, multiply the two dimensions: 12 ft. x 10 ft. = 120 sq.

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3 years ago

Rupees500 for 3years at 5 percent?

Naya [18.7K]

What's the question?

6 0

3 years ago

Use sigma notation to represent the sum of a geometric series with a first term of 3 and a common ratio of . A. B. C. D.

maksim [4K]

Answer:

$\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]$

Step-by-step explanation:

A geometric sequence is a list of numbers having a common ratio. Each term after the first is gotten by multiplying the previous one by the common ratio.

The first term is denoted by a and the common ratio is denoted by r.

A geometric sequence has the form:

a, ar, ar², ar³, . . .

The nth term of a geometric sequence is $ar^{n-1}$

Therefore the sum of the first n terms is:

$\Sigma_{k=1}^{n}(ar^{k-1})$

Given a geometric series with a first term of 3 and a common ratio of 10/9, the sum of the first n terms is:

$\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]$

5 0

3 years ago

Garcia's Grill offers 77 side dishes, 55 types of steak, and 88 toppings. How many different smothered steak dinners can be made

svet-max [94.6K]

Answer:

Therefore the total number of ways that the customer can order the smothered steak dinner is 9800.

Step-by-step explanation:

There are 7 side dishes, and types of stake and 8 toppings.

The customer will have a smothered steak dinner.

The smothered steak dinner will consist of steak and 3 different toppings and 4 $\binom{8}{3} = \frac{8!}{3! \times 5!} = 56$ different side dishes.

The number of ways steak can be selected is = $\binom{5}{1} = \frac{5!}{1! 4!} =5$

The number of ways toppings can be chosen is = $\binom{8}{3} = \frac{8!}{3! 5!} = 56$

The number of ways side dishes can be chosen = $\binom{7}{4} = \frac{7!}{4!3!} = 35.$

Therefore the total number of ways that the customer can order the smothered steak dinner is

= 5 × 56 × 35 = 9800.

7 0

3 years ago

6y+4−3y−7=3(y−1) How many solutions are for this?

Kryger [21]

Answer:

Infinite amount of solutions.

General Formulas and Concepts:

Order of Operations: BPEMDAS
Regular + Equality Properties

Step-by-step explanation:

Step 1: Define equation

6y + 4 - 3y - 7 = 3(y - 1)

Step 2: Solve for y

Combine like terms: 3y - 3 = 3(y - 1)
Distribute 3: 3y - 3 = 3y - 3
Subtract 3y on both sides: -3 = -3

Here we see that there will be infinite amount of solutions. We can plug in any number y and it will render the equation true.

8 0

3 years ago

Read 2 more answers