For what value(s) of k will the function y=6x^2-8x+k have

After four years of college, Erica has to start paying off all her student loans. Her first payment is due at the end of this mo

tatiyna

Answer:

Therefore, the approximate monthly payment is $548.85

Step-by-step explanation:

The amount of student loans Erica currently has = $34,006.00

The duration over which Erica is to pay back the loan = 7 years

The annual interest rate for the loan = 9.1%

Therefore, we have the geometric sequence formula is given as follows;

$A_n = P( 1 + r)^n - M \times \left [ \dfrac{(1 + r)^n-1}{r} \right ]$

Where;

M = The monthly payment

P = The initial loan balance = $34,006.00

r = The annual interest rate = 9.1%

n = The number of monthly payment = 7 × 12 = 84

Aₙ = The amount remaining= 0 at the end of the given time for payment

Substituting the values into the above formula, , we get;

$0 = 34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84} - M \times \left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]$

$M = \dfrac{34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84} }{\left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]} \approx 548.85$

Therefore, the approximate monthly payment = $548.85

6 0

3 years ago

Put the following equation of a line into slope-intercept form, simplifying all

balandron [24]

Answer:

$y=-x+8$

Step-by-step explanation:

$3x+3y=24\\\\3x-3x+3y=24-3x\\\\3y=24-3x\\\\\frac{3y=24-3x}{3}\\\\y=8-x\\\\\boxed{y=-x+8}$

Hope this helps.

7 0

3 years ago

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8. Write an equation of the line that passes through (-2, 3) and is parallel to the line y = 2x - 1.

Wittaler [7]

Answer:

y=2x+7

Step-by-step explanation:

7 0

3 years ago

Write an equation in slope-intercept form for the line that passes through the points (6,-3) and

Vinvika [58]

Answer:

y = - $\frac{5}{6}$ x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (6, - 3) and (x₂, y₂ ) = (0, 2)

m = $\frac{2+3}{0-6}$ = $\frac{5}{-6}$ = - $\frac{5}{6}$ , thus

y = - $\frac{5}{6}$ x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (6, - 3), then

- 3 = - 5 + c ⇒ c = - 3 + 5 = 2

y = - $\frac{5}{6}$ x + 2 ← equation of line

8 0

3 years ago

Triangle HIJ has been reflected to create triangle H'I'J'. Segment HJ= H'J'= 4, segments IJ = I'J' = 7, and angles J and J' are

svlad2 [7]

The postulate that prove that the two triangles in your problem is congruent is SAS or Side Angle Side postulate. This postulate is use when the given of an equation are only 2 side and an angle and also it gives the answer or the side on which the angle is projected. By means of that you can tell or figure out that the two triangle is congruent. So the answer is letter B. SAS

8 0

4 years ago

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