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Anastaziya [24]

3 years ago

6

For what value(s) of k will the function y=6x^2-8x+k have

1 answer:

liubo4ka [24]3 years ago

8 0

Think the answer is a

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The probability distribution for a random variable x is given in the table X: -5,-3,-2,0,2,3 Probability: .17,.13,.33,.16,.11,.1

Ivan

Answer:

0.6 probability that $-2 \leq x \leq 2$

Step-by-step explanation:

The probability distribution is given in the table.

Probability that x is between -2 and 2.

Between -2 and 2, inclusive, we have -2, 0 and 2. So

$P(-2 \leq x \leq 2) = P(X = -2) + P(X = 0) + P(X = 2)$

From the table:

$P(X = -2) = 0.33, P(X = 0) = 0.16, P(X = 2) = 0.11$ . So

$P(-2 \leq x \leq 2) = P(X = -2) + P(X = 0) + P(X = 2) = 0.33 + 0.16 + 0.11 = 0.60$

0.6 probability that $-2 \leq x \leq 2$

4 0

3 years ago

Which expression is equivalent to 4(5 − 3) <br><br> 9 − 3<br><br> 8x<br><br> 20 − 12<br><br> 8 + 1

Ludmilka [50]

The correct answer is 20- 12

4 0

2 years ago

During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time

Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

$\frac{dP}{dt} = Pr$

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

$\frac{dP}{P} = r dt$

$\int \frac{dP}{P} = \int r dt$

$\ln{P} = rt + K$

Applying the exponential to both sides:

$P(t) = Ke^{rt}$

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

$P(t) = 300e^{rt}$

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

$P(t) = 300e^{rt}$

$1000 = 300e^{24r}$

$e^{24r} = \frac{1000}{300}$

$e^{24r} = \frac{10}{3}$

$\ln{e^{24r}} = \ln{\frac{10}{3}}$

$24r = \ln{\frac{10}{3}}$

$r = \frac{\ln{\frac{10}{3}}}{24}$

$r = 0.05$

So

$P(t) = 300e^{0.05t}$

At what time t is the population 500?

This is t for which P(t) = 500. So

$P(t) = 300e^{0.05t}$

$500 = 300e^{0.05t}$

$e^{0.05t} = \frac{500}{300}$

$e^{0.05t} = \frac{5}{3}$

$\ln{e^{0.05t}} = \ln{\frac{5}{3}}$

$0.05t = \ln{\frac{5}{3}}$

$t = \frac{\ln{\frac{5}{3}}}{0.05}$

$t = 10.22$

The population is of 500 after 10.22 hours.

7 0

2 years ago

5x+17=-8 solve the equation

kirill115 [55]

5x=-8-17

5x=-25

x=-25/5

x=-5

7 0

3 years ago

Does (2, -1) make this a true statement? Why or why not?<br> 3x + 2y = 4

kvv77 [185]

Answer: Yes

Step-by-step explanation:

So a coordinate pair is always set up (x,y) so you plug the x term in the coordinate pair into the x in the equation and the y term in for the y. 3×2 + 2×-1. Multiply them together and you end up with 4.

3 0

3 years ago