Let

. Then

and

are two fundamental, linearly independent solution that satisfy


Note that

, so that

. Adding

doesn't change this, since

.
So if we suppose

then substituting

would give

To make sure everything cancels out, multiply the second degree term by

, so that

Then if

, we get

as desired. So one possible ODE would be

(See "Euler-Cauchy equation" for more info)
D)4 is the answer jcidifodofif
C: 3(-8+1)=3(-8)+3(1)
If this doesn’t help rate it 1 star at least
<em><u>Question:</u></em>
You have a 32-foot fence around a square garden. There are 4 equal sections. You paint 1/3 of one section of the fence. What fraction of the fence did you paint?
<em><u>Answer:</u></em>
The fraction of the fence painted is 
<em><u>Solution:</u></em>
Given that:
You have a 32-foot fence around a square garden. There are 4 equal sections
<em><u>Find the length of each section:
</u></em>
4 sections = 32 foot

<em><u>Find the length that is painted:
</u></em>

Therefore
foot of fence is painted
<em><u>Find the fraction that that is painted:</u></em>
Total length of fence = 32

Therefore
fraction of the fence is painted
I hope this helps:
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