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damaskus [11]
3 years ago
6

Graph the equation on the coordinate plane. y=1/2x it can't be (0,0)

Mathematics
1 answer:
MArishka [77]3 years ago
4 0
You would graph this the same way you would any other y = mx + b equation, only, in this case, there isn't a y-intercept present in the equation. it's just y = mx.

y = 1/2x -- what you do is plug in x-values, then get the y-value and graph the point. choose easy numbers so the math won't cause you too much trouble (numbers like 1, 2, -1, and -2 are usually easy enough).

when x = 1...
y = (1/2)(1)
y = 1/2
(1, 1/2)

when x = -1...
y = (1/2)(-1)
y = -1/2
(-1, -1/2)

when x = 2...
y = (1/2)(2)
y = 1
(2, 1)

when x = -2...
y = (1/2)(-2)
y = -1
(2, -1)

that should be enough to sketch a graph. if you need more points, just follow the same process and plug more x-values in to get your y-values.
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PLEASE HELP AND SHOW WORK IF YOU CAN​
Murljashka [212]

Answer:

c) XY > RS

= true

Step-by-step explanation:

Firstly know the meaning of each sign given

> means <u>is greater than</u>

= means <u>is equal to</u>

a)XZ > ST

XZ = 8

ST = 11 - greater

= false

b) XY = RS

Due to the angles presented, we conclude that the greater the angle, the longer the unmeasured line.

XY is longer than RS

= false

c) XY > RS

= true

d) RS > XY

RS is shorter than XY hence not greater.

= false

3 0
3 years ago
Choose the correct simplification.
iren [92.7K]

Answer:

x^3y^6z^3 is correct

Step-by-step explanation:

Taking an exponent to the power of an exponent means multiplying the exponents together.

So y^2^3 is the same as y^(2*3) or y^6

Hope that made sense!

5 0
3 years ago
Plz helpppppp!!!!!!!
ira [324]

The answer is D.

Can I please get brainliest

4 0
3 years ago
Read 2 more answers
yeah uh well hi I don't want to do my sister hw well here's 50 points pls solve both problems and tell me the area and if ur a t
Korvikt [17]

You shouldn't have to do your sister's hw. Btw, the answer for the first one is 224 and the answer for the second is 229.

3 0
3 years ago
would someone be able to explain to me how to solve these problems? I don't need the solutions, I just need an explanation. I ne
Leni [432]
The first 3  are examples of the difference of 2 squares so you use the identity 
a^2 - b^2 = (a + b)(a - b)
x^2 - 49 = 0 
so (x + 7)(x - 7) = 0
so either x + 7 = 0 or x - 7 = 0
giving x = -7  and 7.
Number 7 reduces to 3x^2 =12, x^2  = 4 so x = +/- 2
Number 8  take out GCf (d) to give 
d(d - 2)  = 0   so d = 0 ,  2
9 and 10 are more difficult to factor
you use the 'ac' method  Google it to get more details
2x^2 - 5x + 2
multiply first coefficient by the constant at the end 
that is 2 * 2 =  4
Now we want  2 numbers  which when multiplied give + 4 and when added give - 5:-    -1 and -4  seem promising so we write the equation as:-

2x^2 - 4x - x + 2 = 0

now factor by grouping 
2x(x - 2) - 1(x - 2) = 0

(x - 2) is common so

(2x - 1)(x - 2) = 0
and 2x - 1 = 0 or x - 2 = 0  and now you can find x.

The last example is solved in the same way.


8 0
3 years ago
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