8mm bc a=lw. If a=32 and l=4, you get 4w=32. Then, solve for w.
<u>Answer:</u>
24
<u>Step-by-step explanation:</u>
Y is 60% of 40
Equation: Y = P% * X
<u>Solving our equation for Y</u>
Y = P% * X
Y = 60% * 40
<u>Converting percent to decimal:</u>
p = 60%/100 = 0.6
Y = 0.6 * 40
Y = 24
Negative since the answer would be -13
First aquarium dimensions:
Length = 6 m.
Width = 4 m and
Height = 2 meter.
Second aquarium dimensions:
Length = 8 m.
Width = 9 m and
Height = 3 meter.
We know formula for volume of a cuboidal box = Length*Width*Height.
Plugging values of length, width and height of first aquarium in formula of volume. We get
V1 = 6*4*2 = 48 m^3.
Plugging values of length, width and height of second aquarium in formula of volume. We get
V2 = 8*9*3 = 216 m^3.
In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.
Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.
Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.
First one
market risk
:))
hope it helped
correct me if i’m wrong
