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mina [271]
3 years ago
6

The magnitude, M, of an earthquake is defined to be M=log I/S, where I is the intensity of the earthquake (measured by the ampli

tude of the seismograph wave) and S is the intensity of a “standard” earthquake, which is barely detectable. What is the magnitude of an earthquake that is 35 times more intense than a standard earthquake? Use a calculator. Round your answer to the nearest tenth.
–1.5?
–0.5?
1.5?
3.6?
Mathematics
2 answers:
Nitella [24]3 years ago
7 0
The answer is 1.5 have a good day
Brilliant_brown [7]3 years ago
6 0
Given:
M = log I/S

M = magnitude
I = intensity of the earthquake
S = intensity of the standard earthquake

The minimum intensity of a standard earthquake is 10.
Intensity of the earthquake is 35 times the standard earthquake. So,
10 x 35 = 350

M = log 350/10
M = log 35
M = 1.544 or 1.5  Third option
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Anastasy [175]

Answer:

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Step-by-step explanation:

The hypothesis provided is:

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The significance level is α = 0.10

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Thus, the null hypothesis will be rejected.

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The null hypothesis is rejected stating that the value of μ is more than 0.

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If the decision in​ (a) is an​ error, i.e. the null hypothesis is rejected when in fact it is true, this type of error is known as type I error.

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