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mina [271]
3 years ago
6

The magnitude, M, of an earthquake is defined to be M=log I/S, where I is the intensity of the earthquake (measured by the ampli

tude of the seismograph wave) and S is the intensity of a “standard” earthquake, which is barely detectable. What is the magnitude of an earthquake that is 35 times more intense than a standard earthquake? Use a calculator. Round your answer to the nearest tenth.
–1.5?
–0.5?
1.5?
3.6?
Mathematics
2 answers:
Nitella [24]3 years ago
7 0
The answer is 1.5 have a good day
Brilliant_brown [7]3 years ago
6 0
Given:
M = log I/S

M = magnitude
I = intensity of the earthquake
S = intensity of the standard earthquake

The minimum intensity of a standard earthquake is 10.
Intensity of the earthquake is 35 times the standard earthquake. So,
10 x 35 = 350

M = log 350/10
M = log 35
M = 1.544 or 1.5  Third option
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2 years ago
How do you solve (2x-7)(5x+3)=0
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Step-by-step explanation:

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Then do 5x+3=0

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3 years ago
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Answer:

Drinks = 6.75

Popcorn= 1

Step-by-step explanation:

Let the popcorn = P

Let the drink = D

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D = 6.75

=========================

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12P + 27 = 39               Subtract 27 from both sides

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12P = 12                        Divide by 12

12P/12 = 12/12

P = 1                               Answer

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3 years ago
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