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2 years ago

12

A man surveyed a sample of 36 high school students and asked, "how many days in the past week have you consumed an alcoholic b

everage?" the results of the survey are shown to the right. use these results to answer parts (a) through (f). 0 1 0 0 0 0 1 0 0 0 0 4 1 5 1 1 0 1 1 0 1 1 0 1 2 0 1 0 1 0 0 1 1 2 3 2 (a) is this data discrete or continuous?

2 answers:

kiruha [24]2 years ago

5 0

This data is discrete because it does not form a straight line when plotting the information on a data graph.

dexar [7]2 years ago

4 0

Answer:

Since from the given problem statement the data values are forming straight line on the graph and they are discrete values.

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1/4x + 3/4 = 1/2 ??????????

mart [117]

Answer:

x = -1

Step-by-step explanation:

1/2 = 2/4

____________________________________________________________

1/4x + 3/4 = 2/4

<u> -3/4 -3/4</u>

1/4x = -1/4

divide by -1/4

x = -1

<em><u>Hope this helped! Have a nice day! Plz mark as brainliest!!!</u></em>

<em><u>-XxDeathshotxX</u></em>

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2 years ago

What is 1.3742 rounded to the nearest tenth?

REY [17]

Answer:

1.4 that is the true answer

Step-by-step explanation:

go to the place right after the decimal and then look at the number next to it.if it is greater the 5 it goes up to 1.4 and it is

6 0

2 years ago

A square carpet of side length 9 feet is designed with one large shaded square and eight smaller, congruent shaded squares, as s

Pepsi [2]

Answer:

$3\sqrt{3} + 72$

Step-by-step explanation:

I attached an image to aid the understanding of the question.

Looking at the image, we see that the 8 shaded parts are congruent, as affirmed in the question as well. And we are told that T = 3, this implies that the area of the square with T as it's side is 9ft². Since all the 8 squares are congruenrt, it means each square has its area to be 9. Therefore, the total area of the 8 shaded squares will be:

$9 \times 8 = 72ft^{2}$

It remains the area of the shaded square with side S.

From the question, we have the following ratio:

$\frac{9}{S} = \frac{S}{T}[\tex]But[tex]\frac{9}{S} = \frac{S}{3}[\tex]Multiplying through by 3S we have27 = S² and this gives:[tex]S = \sqrt{27} = 3\sqrt{3}$

I did not add ± because length is always positive, so the case of negative is eliminated.

Now the areas of S is $3\sqrt{3}$

Therefore, the total area of the shaded squares is

$3\sqrt{3} + 72$

3 0

2 years ago

D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

2 years ago

What is the rate of change for this function? 29. y = 5

Verdich [7]

Correct answer is (0,5)

6 0

2 years ago