Answer:
pushes it forward, pushes it backwards and then it moves
Answer:
62.1 ft
Explanation:
We know that
hence 240 gpm will be
From the formula of obtaining efficiency
and making
the subject we have
where Q is flow rate,
is specific weight of water,
is actual head rise and
is the power input to the compressor
Substituting 0.62 for
, 6hp for
,
for
and
for Q then
Therefore, actual head rise of the water being pumped is 62.1 ft
Answer:
The value of developed electric force is ![3.516\times 10^{- 7} N](https://tex.z-dn.net/?f=3.516%5Ctimes%2010%5E%7B-%207%7D%20N)
Solution:
As per the question:
Mass of the droplet = 1.8 mg = ![1.8\times 10^{- 6} kg](https://tex.z-dn.net/?f=1.8%5Ctimes%2010%5E%7B-%206%7D%20kg)
Charge on droplet, Q = ![25 pC = 25\times 10^{- 12} C](https://tex.z-dn.net/?f=25%20pC%20%3D%2025%5Ctimes%2010%5E%7B-%2012%7D%20C)
Distance between the 2 droplets, D = 0.40 cm = 0.004 m
Now, the Electrostatic force given by Coulomb:
![F_{E} = \frac{1}{4\pi epsilon_{o}}.\frac{Q^{2}}{D^{2}}](https://tex.z-dn.net/?f=F_%7BE%7D%20%3D%20%5Cfrac%7B1%7D%7B4%5Cpi%20epsilon_%7Bo%7D%7D.%5Cfrac%7BQ%5E%7B2%7D%7D%7BD%5E%7B2%7D%7D)
![\frac{1}{4\pi epsilon_{o}} = 9\times 10^{9} m/F](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%5Cpi%20epsilon_%7Bo%7D%7D%20%3D%209%5Ctimes%2010%5E%7B9%7D%20m%2FF)
![F_{E} = (9\times 10^{9}).\frac{(25\times 10^{- 12})^{2}}{0.004^{2}}](https://tex.z-dn.net/?f=F_%7BE%7D%20%3D%20%289%5Ctimes%2010%5E%7B9%7D%29.%5Cfrac%7B%2825%5Ctimes%2010%5E%7B-%2012%7D%29%5E%7B2%7D%7D%7B0.004%5E%7B2%7D%7D)
![F_{E} = 3.516\times 10^{- 7} N](https://tex.z-dn.net/?f=F_%7BE%7D%20%3D%203.516%5Ctimes%2010%5E%7B-%207%7D%20N)
The magnitude of force is too low to be noticed.
Answer:
Option B. 0.3 Hz
Explanation:
From the question given above, the following data were obtained:
Period (T) = 3 s
Frequency (f) =?
Frequency is related to the period according to the following equation:
Frequency (f) = 1 / period (T)
f = 1/T
With the above formula, we can obtain the frequency wave as illustrated below:
Period (T) = 3 s
Frequency (f) =?
f = 1/T
f = 1/3
f = 0.3 Hz
Therefore, the frequency of the wave is 0.3 Hz
This would most likely be considered speed.