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Nady [450]
3 years ago
6

Matthew drives 10 meters to go to the park at her the park he goes to the movie theatre which is 15 meters away from the park. H

e then comes back home which is 10 meters away from the park. Find the displacement Mathew travels
Physics
1 answer:
Step2247 [10]3 years ago
4 0

Answer: 0 m

Explanation:

Let's begin by stating clear that movement is the change of position of a body at a certain time. So, during this movement, the body will have a trajectory and a displacement, being both different:

The trajectory is the <u>path followed by the body</u> (is a scalar quantity).  

The displacement is <u>the distance in a straight line between the initial and final position</u> (is a vector quantity).

According to this, in the description Matthew's home is placed at 0 on a number line, then he moves 10 m to the park (this is the distance between the park and Mattew's home), then 15 m to the movie theatre until he finally comes back to his home (position 0). So, in this case we are talking about the <u>path followed by Matthew</u>, hence <u>his trajectory</u>.

However, if we talk about Matthew's displacement, we have to draw a straight line between Matthew's initial position (point 0) to his final position (also point 0).

Now, being this an unidimensional problem, the displacement vector for Matthew is 0 meters.

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An ion accelerated through a potential difference of 115 V experiences an increase in kinetic energy of 7.37 x 1017 J. Calculate
riadik2000 [5.3K]

Answer: 6.408(10)^{-19} C

Explanation:

This problem can be solved by the following equation:

\Delta K=q V

Where:

\Delta K=7.37(10)^{-17} J is the change in kinetic energy

V=115 V is the electric potential difference

q is the electric charge

Finding q:

q=\frac{\Delta K}{V}

q=\frac{7.37(10)^{-17} J}{115 V}

Finally:

q=6.408(10)^{-19} C

4 0
3 years ago
A meteoroid is moving towards a planet. It has mass m = 0.78×109 kg and speed v1 = 4.1×107 m/s at distance R1 = 2.8×107 m from t
wariber [46]

Answer:

PE=81.755\, J

Explanation:

Given that:

  • mass of meteoroid, m=7.8\times 10^8 \,kg
  • radial distance from the center of the planet, R= 2.8\times 10^7 m
  • mass of the planet, M=4.4\times 10^{25}\, kg

<u>For gravitational potential energy we have:</u>

PE=G\frac{M.m}{R}

substituting the respective values:

PE=6.67\times 10^{-11}\times \frac{4.4\times 10^{25}\times 7.8\times 10^8}{2.8\times 10^7}

PE=81.755\, J

5 0
3 years ago
Recent findings on the topic of brain based research indicate all of the following except
Gre4nikov [31]
The answer is D, the brain actually stops growing around age 18
5 0
3 years ago
If the magnet is now pushed into the coil and then held stationary inside the coil describe fully what would you observe on the
alexira [117]

Answer:

E = q V B     describes the electric field induced

E Proportional to V B

while the magnet is pushed into the coil the induced field (B) will increase (consider 1 turn of the coil)

If V is constant the E-field will increase due to increasing B and the galvanometer will deflect accordingly

When V drops to zero the deflection must again be zero

So one would see a blip due to the deflection of the galvanometer

Note that as V increases the galvanometer will deflect one way and then as V drops to zero the deflection will be opposite (drop to zero when V is zero)

B always increases to a constant value because of the properties of the magnet.

8 0
2 years ago
As the distance from a charged particle, "q", increases, what happens to the electric potential?
mr Goodwill [35]

As the distance from a charged particle, "q", increases, the electric potential decreases.

<h3>Electric potential between particles</h3>

The electric potential between particles is the work done in moving a unit charge from infinity to a certain point against the electrical resistance of the field.

V = Kq/r

where;

  • K is Coulomb's constant
  • q is the magnitude of the charge
  • r is the distance between the charges

Thus, from the formula above, as the distance from a charged particle, "q", increases, the electric potential decreases.

Learn more about electric potential here: brainly.com/question/14306881

#SPJ1

6 0
1 year ago
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