PLEASE HELP!!!!Ned wrote the following statement:

Mathematics

2 answers:

lys-0071 [83]2 years ago

4 0

I think is the second choice!!!
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8_murik_8 [283]2 years ago

4 0

Your Answer Would End Up Being: <span>Ned is incorrect, because the triangle described cannot be drawn with the given information.</span>

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A seagull flying in the air over water drops a crab from a height of 45 feet.The distance the crab is from the water as it falls

jonny [76]

For the seagull to catch the crab, h(t)=g(t) so:

-16t^2+45=-13t+23 add 16t^2 to both sides

45=16t^2-13t+23 subtract 45 from both sides

16t^2-13t-22=0 using the quadratic equation:

t=(13±√1577)/32, since t>0

t=(13+√1577)/32 seconds

t≈1.65 seconds (to nearest hundredth of a second)

And the height that this occurs using either original equation is:

h((13+√1577)/32)≈1.59 ft (to nearest hundredth of a foot)

7 0

3 years ago

Evaluate the expression for b = 0 and c= -11.<br> bc + b

avanturin [10]

Answer:

If b = 0 and c = -11, all you have to do is plug in the values into bc + b:

Step-by-step explanation:

(0)(-11) + 0 = 0

3 0

2 years ago

Read 2 more answers

Does anyone know how to do this ?

goldenfox [79]

Answer: D) 32

Step-by-step explanation:

The area of a parallelogram equals its base times its height. Substitute the base and area into this formula to solve for the height:

A=bh

40=(5)(h)

h=8

If ABCD is a parallelogram, opposite sides are parallel, so AB is parallel to DC. If AB is parallel to DC, EB is parallel to DC. Since EB is parallel to DC, quadrilateral EBCD has at least one pair of parallel sides, making it a trapezoid. The area of a trapezoid is equal to $\frac{h(b_{1}+b_{2}) }{2}$ where h is the height, $b_{1}$ is one base, and $b_{2}$ is the other base. Plug the necessary values into the formula: