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Colt1911 [192]
4 years ago
12

Find the midpoint of the segment from point a (6,3) to point B (8,1)

Mathematics
2 answers:
velikii [3]4 years ago
5 0

Answer: M=(7,2)

Step-by-step explanation:

You need to use the following formula:

 M=(\frac{x_A+x_B}{2},\frac{y_A+y_B}{2})

Given the points A(6,3) and B(8,1), you can identify that:

x_A=6\\x_B=8\\y_A=3\\y_B=1

Now, you can substitute these values into the formula M=(\frac{x_A+x_B}{2},\frac{y_A+y_B}{2}).

Therefore, you get this result:

M=(\frac{6+8}{2},\frac{3+1}{2})

M=(7,2)

LUCKY_DIMON [66]4 years ago
4 0

ANSWER

The midpoint is (7,2)

EXPLANATION

The midpoint is calculated using the formula:

M(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

The x-coordinate of the midpoint is given by

x =  \frac{6 + 8}{2}

x =  \frac{14}{2}  = 7

The y-coordinate of the midpoint is given by:

y =  \frac{3 + 1}{2}

y =  \frac{4}{2}  = 2

The midpoint is (7,2)

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kotykmax [81]

Answer:

Step-by-step explanation:

The volume of a cube is given by the formula :

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So now we have to cube these lengths :

Part A :

(3x²y)³ =

(3x²y)(3x²y)(3x²y) =

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Part B:  

(5y²)³ =

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Hope this helped and have a good day

5 0
2 years ago
45% of Ms. Stacey's students will go on a field trip to the museum. If 90 of Ms. Stacey's students went to the museum field trip
g100num [7]

Answer:

c

Step-by-step explanation:

Number of students = number of students that went to the museum / percentage of students that went to the museum

90 / 0.45 = 200 students

4 0
3 years ago
Brandon works at a small petting zoo with 8 animals. He was looking at some data showing the masses of the animals. Each animal
insens350 [35]

Answer:

<em>OPtion B. Both the mean and median will increase, but the mean will increase by more than the median.</em>

<em />

Explanation:

You should not need to do calculations to determine <em>how buying the horse affects the mean and median.</em>

Without the horse, there are 8 animals. When the data are ordered, the <em>median</em> is the average of the 4th and the 5th weights: (7 + 27)/2.

With the horse, there are 9 animals. The median will be the 5th weight: 27

Then, the median increases from (7 +27)/2 to 27.

What about the <em>mean</em>?

The horse's weight is well beyond the weight of the other 8 animals. The range increases from 160 - 2 = 158 to 900 - 2 = 898.

Then, when you calculate the mean inlcuding the weigth of the horse, there will be a high increase.

Thus, without further calculations, you can conclude that "<em>B. Both the mean and median will increase, but the mean will increase by more than the median"</em>

7 0
3 years ago
Read 2 more answers
suppose you know that over the last 10 years, the porbabiliy that your town would have at least one ma jor stor was 40%. describ
Anuta_ua [19.1K]

Answer:

The probability of a big storm is 40%.

Now, you can find a D10 (a die with 10 faces)

You can assign 4 numbers (0, 1, 2, 3) to the event "there is a major storm"

in this way, you have 40% of having a storm.

and the other 6 numbers (4, 5, 6, 7, 8, 9) to the event "there is not a major storm". This means that we have 60% of not having a storm.

now, when you roll the dice you can see if a year there will be a storm or not.

Now, you roll the dice 5 times (for the 5 years) and take note of the results and the number of storms in those 5 rolls.

Now do the same thing a bunch of times, at least 25 times.

Now, you recorded the results in each set of rolls, now see the number of sets that have at least years with storms.

Take that number and divide it by the total number of sets of data (in this case 25, for example)

The result is the probability that we are looking for.

6 0
3 years ago
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