All categories

3 years ago

Gema has 4 FT of wire how much wire does she need to wrap one meter of her garden?

Mathematics

1 answer:

Dmitry [639]3 years ago

4 0

Answer:

3.28 feet

Step-by-step explanation:

One meter equals to 3.28 feet.

The question isn't exactly clear what Gema wants to use her wire for, because "wrap one meter" isn't correct.

You wrap something around something else... and you can't wrap something around a meter. You can wrap around a square meter by doing the perimeter... but then you'd need more than meter to do the perimeter of a square meter (the perimeter can be around 4 meters).

So, assuming she has a length of 1 meter to cover, she would need 3.28 feet.

You might be interested in

Simplify each expression for x 4<br> a. -5x4<br> b. 7x-3

kirill [66]

Does x equal 4 ?if it does then a) -100
b) 25

4 0

3 years ago

Help Me on this palzz

eimsori [14]

Answer:

That should be 11.99+35.50+6.75+3+ 7.15% of EACH of those items added together minus 11.99+35.50+6.75+3+ 6.35% of EACH of the same items added together

6 0

3 years ago

A cube has a surface area of 486 cm2. What is the side length ?

astraxan [27]

A Cube, has all equal sides, namely, the length, width and height
are all equal to each other

so.. notice the picture added here
you have really, 6 squares, stacked up to each other at the edges

so...what is the Area of one of those squares?
well, if the sides are equal, let's say the side is "x" long, then
the Area is $x\cdot x \implies x^2$

well, you have 6 of those squares, thus $\bf \textit{surface area of a cube}=
\begin{cases}
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)\\
 --------------\\
 x^2+x^2+x^2+x^2+x^2\\
6x^2
\end{cases}
\\\\
\textit{we know the Area is }486\ cm^2\qquad thus
\\\\
\textit{surface area}=6x^2\implies 486=6x^2$

solve for "x", to get one side's length

3 0

3 years ago

What is the area of the rectangle shown below?

krek1111 [17]

Your answer is 8 times 4 is 32.

4 0

3 years ago

Read 2 more answers

Ms.Lamberson got a new puppy abd weighed it in September and October in September the Puppy Weighed9 and one Fourth pounds In Oc

ddd [48]

Answer: The puppy was $2.25\ lb$ havier in October that it was in September.

Step-by-step explanation:

You need to make the conversion from mixed numbers to decimal numbers. To do it, divide the numerator of the fraction by the denominator add the result to whole part number:

$9\frac{1}{4}=9+0.25=9.25\\\\11\frac{1}{2}=11+0.5=11.5$

The weight of the puppy in September was:

$w_1=9.25\ lb$

And its weight in October was:

$w_2=11.5\ lb$

Subtract its weight in September from its weight in October in order to find how much heavier the puppy was in October than it was in September:

$w_2-w_1=11.5\ lb-9.25\ lb=2.25\ lb$

8 0

3 years ago