Unfortunately there isn't enough information.
Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.
Answer:
5/16m long.
Step-by-step explanation:
- 5/8 ÷ 2/1
- 5/8 × 1/2
- =5/16m long.
Answer:
x = 4
y = 1
Step-by-step explanation:
x = 3y + 1 (Multiply everything by -2)
2x + 4y = 12 (Transfer 4y to the right of the = sign)
2x = -4y + 12
-2x = -6y - 2
0 = -10y + 10
-10 = -10y
y = 1
x = 3y + 1
x = 3(1) + 1
x = 3 + 1
x = 4
3 terms
5x, 2x^2, -8
2nd degree
highest exponent is 2
2nd degree polynomial (3 terms)
Answer:
A) 2/15
Step-by-step explanation:
So just divide it normally, do keep change flip
2/3*1/5
2/3 keep
divison change
Denomeinator, flip it, 5 to 1/5
now multiply
2/15
