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1 year ago

Write the standard form of the equation of a circle with radius 3 and center (11, 3)

Mathematics

2 answers:

skad [1K]1 year ago

7 0

Answer:

(x+11)2+(y−3)2=81

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Step-by-step explanation:

Talja [164]1 year ago

4 0

Answer:

x² - 22x + y² - 6y + 121 = 0

Step-by-step explanation:

General Form of Equation

(x - h)² + (y - k)² = r²

Solving

(x - 11)² + (y - 3)² = (3)²
x² - 22x + 121 + y² - 6y + 9 = 9
x² - 22x + y² - 6y + 121 = 0

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I need to know what the answer to that question is and I need to know how to do it

mel-nik [20]

Answer:

$\frac{59}{8} or 7\frac{3}{8}$

Step-by-step explanation:

$\frac{80}{4} - 12\frac{5}{8}$

First you need to make the 12 5/8 into an improper fraction by multiplying 12 by 8 and then adding the total by 5.

$12\frac{5}{8}$ -> $\frac{101}{8}$

Now you have $\frac{80}{4} - \frac{101}{8}$ so you need a common denominator by multiplying the first fraction by 2

$\frac{80}{4} -> \frac{160}{8}$

Then you subtract 160 - 101 which equals 59.

$\frac{59}{8} or 7\frac{3}{8}$

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3 years ago

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