Question

The sides of a triangle are x, x+7, and 2x-8. If the perimeter of the triangle is 47, what is x

Answer 1

just like the previous one, we sum the sides to get the perimeter.

$\bf (x)+(x+7)+(2x-8)=47\implies 4x-1=47\implies 4x=48\\\\\\x=\cfrac{48}{4}\implies x=12$