What is 59% of 14 m?

Ken's fitness member ship cost $100 to join plus a $25 monthly fee. Ken also used a coupon to get 10% off the monthly fee. What

GREYUIT [131]

The equation that models the total cost is y = 100 + 22.5m

Step-by-step explanation:

Fitness member ship cost = $100

Monthly fee = $25

Discount = 10% on monthly fee

To calculate new monthly fee after discount,

25 - (25*10%) --> 25 - 2.5 --> $22.5

Number of months = m

Fee in m months = 22.5*m = 22.5m

<u>Equation:</u>

(c) is constant which is the membership fee

(x) is the monthly fee $22.5

(m) is the number of months

(y) is the total cost

So,

y = mx + c

y = m(22.5) + 100

y = 100 + 22.5m

Therefore, the equation that models the total cost is y = 100 + 22.5m

Keyword: Equation

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5 0

2 years ago

Roland’s Boat Tours sells deluxe and economy seats for each tour it conducts. In order to complete a tour, at least 1 economy se

Anna11 [10]

Answer:

$1170

Step-by-step explanation:

Let the sells for economy seats be =x

Let the sells for deluxe seats be=y

The inequalities that can be obtained are;

x≥1 --------------------at least 1 economy seats

y≥6 --------------------at least 6 deluxe seats

x+y=30-----------------maximum number of passengers allowed on each boat

Graph the inequalities

Use the graph tool to locate the point of maximum profit.The intersecting point for the three graphs

The point is (24,6)

Hence, x=24 and y=6

Profit for each

Economy seats 24×$40=$960

Deluxe seats 6×$35=$210

Maximum profit for one tour

$960+$210=$1170

3 0

3 years ago

Simplify 9 x 5/9<br> in 4 mins

Triss [41]

Answer:

5

Step-by-step explanation:

9 x 5/9

9/1 * 5/9

Rewriting

9/9 * 5/1

1 * 5/1

5

6 0

2 years ago

Read 2 more answers

How do you calculate the common difference?

SCORPION-xisa [38]

Answer:

<h3> second term minus first term </h3>

Step-by-step explanation:

Difference is a result of subtracting (not dividing!)

To calculate difference between two terms we have to subtract the previous from the next:

$d=a_2-a_1=a_3-a_2=a_4-a_3=...=a_n-a_{n-1}$

7 0

2 years ago

Mark the statement either true (in all cases) or false (for at least one example). If false, construct a specific example to sho

LUCKY_DIMON [66]

Answer with Step-by-step explanation:

We are given that $v_1,v_2,..,v_4$ are in $R^4$ and $v_1,v_2,v_3$ is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

We have to find that given statement is true or false.

Dependent vectors:Dependent vectors are those vectors in which atleast one vector is a linear combination of other given vectors.

Or If we have vectors $x_1,x_2,....x_n$

Then their linear combination

$a_1x_1+a_2x_2+.....+a_nx_n=0$

There exist at least one scalar which is not zero.

If $v_1,v_2,v_3$ are dependent vectors then

$a_1v_1+a_2v_2+a_3v_3=0$ for scalars $a_1,a_2,a_3$

Then , by definition of dependent vectors

There exist a vector which is not equal to zero

If vector $v_3$ is a linear combination of $v_1\;and \;v_2$ , So at least one of vectors in the set is a linear combination of others and the set is linearly dependent.

Hence, by definition of dependent vectors

{ $v_1,v_2,v_3,v_4$ } is linearly dependent.

Option B is true.

8 0

3 years ago