Concluimos que a partir de 21 piezas se gana más en la empresa B.
<h3>
¿Cuanto debe vender para que le paguen más en la empresa B?</h3>
Si definimos el número de piezas vendidas como x, la cantidad que le pagan en la empresa A es:
A(x) = $6000 + $20*x
Y lo que le pagan en la empresa B es:
B(x) = $6000 + x^2
Queremos ver para que valor de x, se da que B(x) > A(x).
Entoces resolvamos esa inequación.
6000 + 20*x < 6000 + x^2
20x < x^2
20 < x
x debe ser más grande que 20, entonces concluimos que a partir de 21 piezas se gana más en la empresa B.
Sí quieres aprender más sobre inecuaciones, puedes leer:
brainly.com/question/23023694
<span>The fact that Helen’s indifference curves touch the axes should immediately make you want to check for a corner point solution. To see the corner point optimum algebraically, notice if there was an interior solution, the tangency condition implies (S + 10)/(C +10) = 3, or S = 3C + 20. Combining this with the budget constraint, 9C + 3S = 30, we find that the optimal number of CDs would be given by 3018â’=Cwhich implies a negative number of CDs. Since it’s impossible to purchase a negative amount of something, our assumption that there was an interior solution must be false. Instead, the optimum will consist of C = 0 and Helen spending all her income on sandwiches: S = 10. Graphically, the corner optimum is reflected in the fact that the slope of the budget line is steeper than that of the indifference curve, even when C = 0. Specifically, note that at (C, S) = (0, 10) we have P C / P S = 3 > MRS C,S = 2. Thus, even at the corner point, the marginal utility per dollar spent on CDs is lower than on sandwiches. However, since she is already at a corner point with C = 0, she cannot give up any more CDs. Therefore the best Helen can do is to spend all her income on sandwiches: ( C , S ) = (0, 10). [Note: At the other corner with S = 0 and C = 3.3, P C / P S = 3 > MRS C,S = 0.75. Thus, Helen would prefer to buy more sandwiches and less CDs, which is of course entirely feasible at this corner point. Thus the S = 0 corner cannot be an optimum]</span>
the 3rd option is the answer. just because it is inexpensive to feed a pet, that does not make it a favorite pet. you can like cats more than dogs but it may be less expensive to feed a dog
Answer:
200 I think I'm not entirely sure
