1a. 3^1 / 3^2 = 3^1-2 = 3^-1 = 1/3^1 = 1/3.
2b. 4^2 / 4^4 = 4^2-4 = 4^-2 = 1/4^2.
3c. 6^3/6^5 = 6^3-5 = 6^-2 = 1/6^2.
4d. 3^-5 • 3^2 = 3^-10 = 1/3^10.
I believe for the last question its asking only to rewrite exponent as a positive exponent similar to the first question.
Answer:
∠4 and ∠3
∠4 and ∠5
∠3 and ∠6.
Step-by-step explanation
Find the diagram attached
First you must note that the sum of two supplementary angles is 180°
Also, since the sum of angle on a straight line is 180°, the angles that are supplementary must lie on the same straight line.
Based on the diagram, the pair of angles that lies on the same straight line are ∠4 and ∠3, ∠4 and ∠5 and ∠3 and ∠6. If that is the case, hence this angles are supplementary.
Answer:
The answer to your question is: when x = 100 days, y = 34 m³
Step-by-step explanation:
Data
Volumen = 61 m³
Loses 0.27 m³ each day
Equation y + 0.27x = 61
when x = 100, y = ?
Process, just substitute x in the equation and solve it for y
y + 0.27(100) = 61
y + 27 = 61
y = 61 - 27
y = 34 m³
It means that after ten days, the swimming pool will only have 34 m³, because 27 m³ will have evaporated.
Answer:
21
Step-by-step explanation:
Try using this notation: a(n) and not an.
an=n^3-2n becomes a(n) = n^3 - 2n.
Then a(1) = 1^3 - 2(1) = 1 - 2 = -1
a(2) = 2^3 - 2(2) = 8 - 4 = 4
a(3) = 3^3 - 2(3) = 27 - 6 = 21
