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3 years ago

Are the ratios 7:5 and 11:10 equivalent

Mathematics

1 answer:

Gekata [30.6K]3 years ago

3 0

No because I said so I didn’t even care what about the money that was

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Lin rode a bike 20 miles in 150 minutes. If she rode at a constant speed, how far did she ride in 15 minutes? How long did it ta

coldgirl [10]

Hey there! :)

Answer:

First part: 2 miles.

Second part: 45 minutes

Third part: 8 mph.

Step-by-step explanation:

We can divide this question into 3 parts.

Begin by solving for the distance traveled after 15 minutes by creating a ratio:

$\frac{20 mi}{150min} = \frac{x}{15 min}$

Cross multiply:

20 · 15 = 150 · x

300 = 150x

300/150 = 150x/150

x = 2 miles.

2nd part: How long it took her to ride 6 miles.

Set up another ratio similar to the one used before:

$\frac{20 mi}{150min} = \frac{6mi}{x min}$

Cross multiply:

20 · x = 6 · 150

20x = 900

20x/20 = 900/20

x = 45 minutes.

3rd part:

For this part, we will need to convert from minutes to hours.

$\frac{20 mi}{150 min}* \frac{60 min}{1 hr} = \frac{1200mi}{150hr} = 8 mi/h$

Therefore, her speed is 8 mph.

5 0

2 years ago

Does pp taste gooddddd

GrogVix [38]

Answer:

ion know

Step-by-step explanation:

7 0

2 years ago

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What is the slope of a line that is perpendicular to the line 2x-4y=24

DanielleElmas [232]

Answer: y= -2x + 24

Step-by-step explanation

2x - 4y = 24

subtract 2x from both sides

divide 4y by 4y to get y by itself

then you get y= -2x + 24

3 0

3 years ago

In in the previous activity you solved a system of equations representing the carnival admissions using the elimination method i

Mariulka [41]

Answer:

The value of a=300 and value of k=200

If you solve the above system of equations by elimination method, you will get the same values of a and k.

In Equation 1 $k+a=500$ both variables k has 1 as their coefficient.

Step-by-step explanation:

We need to solve the system of equations using substitution method

The equation are:

$k + a = 500--eq(1)\\3k + 10a = 3,600 --eq(2)$

For substitution method, we find value of k from equation 1 and put in equation 2

$From \ eq(1) \ we \ get\\k=500-a$

Putting it in eq(2)

$3k+10a=3600\\Put \ k=500-a\\3(500-a)+10a=3600\\1500-3a+10a=3600\\7a=3600-1500\\7a=2100\\a=\frac{2100}{7}\\a=300$

So, we get value of a = 300

Now finding value of k by putting value of a in equation $k=500-a$

$k=500-a\\Putting \ a \ =500\\k=500-300\\k=200$

So, we get value of k =200

The value of a=300 and value of k=200

If you solve the above system of equations by elimination method, you will get the same values of a and k.

In Equation 1 $k+a=500$ both variables k has 1 as their coefficient.

4 0

2 years ago

Luiza delivers newspapers in her neighborhood. If you plot the points (−1, 1), (4, 1), (4, −2) and (−1, −2), you will create a r

wel

The first thing to do in this case is to draw the ordered pairs in the Cartesian plane and join the points.
We have then that the resulting figure is a rectangle.
We must find the perimeter of the rectangle that is given by:
P = 2L + 2W
Where,
L: long
W: width
Restoring the values:
P = 2 * (5) + 2 * (3)
P = 16
Answer:
her route cover 16 miles.

5 0

3 years ago

Read 2 more answers