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VladimirAG [237]
3 years ago
12

Which expression is equivalent to 2x-2(20-3x)+12

Mathematics
1 answer:
Darina [25.2K]3 years ago
6 0

Answer:

-7x-48

Step-by-step explanation:

2x-3(20-3x)+12

2x-60-9x+12     (distribute)

-7x-48

hope this helps

brainliest?

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Graph the function by making a table of values which table is correct
Talja [164]

It is often more convenient to evaluate a polynomial when it is written is "Horner form."

... f(x) = (((10x -4)x -8)x +3)x -6

The graphs offered can be distinguished by their values of f(1) and f(2), so our table can be a short one.

... f(1) = (((10·1 -4)1 -8)1 +3)1 -6 = -5 . . . . . . . eliminates graph d

... f(2) = (((10·2 -4)2 -8)2 +3)2 -6 = 96 . . . . eliminates graphs a and c

The appropriate choice is b.

3 0
3 years ago
A rectangular sign has length of 3 and 1/2 ft and a width of 1 and 1/8 ft. Will the area of the sign be greater or less than 3 a
zavuch27 [327]

Answer:

Area = 3\dfrac{15}{16}\ sq\ ft

Area is greater than 3\frac{1}{2} sq ft.

Step-by-step explanation:

Length of rectangular sign board = 3\frac{1}{2} ft

Width of rectangular sign board = 1\frac{1}{8} ft

Area of a rectangle is given by the formula:

A = Length \times Width

To find the area, we are going to multiply 3\frac{1}{2} with 1\frac{1}{8}.

1\frac{1}{8} is greater than 1.

Therefore the multiplication will be greater than 3\frac{1}{2}.

Hence, we can say that area will be greater than 3\frac{1}{2} sq ft.

Area of the sign:

A = 3\dfrac{1}{2}\times 1\dfrac{1}8\\\Rightarrow A = \dfrac{7}{2}\times \frac{9}8\\\Rightarrow A = \dfrac{63}{16}\\\Rightarrow A = 3\dfrac{15}{16}\ sq\ ft

8 0
3 years ago
Plss finish fast the question is linked thank you for ur help
kobusy [5.1K]

Answer: B. 2 2/5

Step-by-step explanation: Hope this help :D

3 0
3 years ago
Read 2 more answers
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Dimas [21]

Answer:

A= 1/2(2x)(x+7)

Step-by-step explanation:

4 0
3 years ago
Is the answer a, b, c, or d.
ale4655 [162]
The correct answer is d.

We have the following system of linear equations:

(I) 4x+7y=-14
(II) 8x+5y=8

Let's use the elimination method, then let's multiply the equation (1) \times(-2) and subtracting (I) and (II):

(I) -2(4x+7y)=-2(-14)
∴ -8x-14y=28

(I) -8x-14y=28
(II) 8x+5y=8
____________________
(III)  -9y=36

∴  y=-4

We can find the value of x by substituting y either in (I) or (II). Thus, from (I):

4x+7(-4)=-14
∴ 4x-28=-14
∴ 4x=14
∴ x=\frac{14}{4}
∴ \boxed{x=\frac{7}{2}}

Let's substitute the values of x and y into (I) and (2)

(I) 4(\frac{7}{2})+7(-4)=14-28=-14
(II) 8(\frac{7}{2})+5(-4)=28-20=8

Finally the answer is:

\boxed{x=\frac{7}{2} \rightarrow x= 3 \frac{1}{2}}

4 0
3 years ago
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