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3 years ago

PLZZZZZ NEED HELP!!!!!!

Mathematics

1 answer:

mylen [45]3 years ago

5 0

Remember the rules of Sohcahtoa (Sine, cosine, tangent). For this problem we take the cosine of 38 because the labeled sides are the adjacent leg and the hypotenuse.

Cos(38)=79/x

Cosine of 38 is about 0.7880

0.7880=79/x

Next we multiply both sides by the denominator

(x) 0.7880=79 (x)

Then divide.

0.7880 0.7880

X=100.25

Hope this helped :)

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3 years ago

Eric’s average income for the first 4 months of the year is $1,450.25, what must be his

drek231 [11]

Answer:

Average income of Eric for the remaining 8 months = $\$1946$

Step-by-step explanation:

Given: Average income of Eric for the first 4 months of the year is equal to $1,450.25

To find: average income for the remaining 8 months so that his average income for the year is $1,780.75

Solution:

Average income = Total income for the year/Total number of months

Average income of Eric for the first 4 months = $1,450.25

So,

Total income of Eric for the first 4 months = 1,450.25 × 4 = 5801

Let x denotes total income of Eric for the remaining 8 months

Total income for the year = 5801 + x

Therefore,

Average income for the year = $\frac{5801+x}{12}$

Also, average income for the year is $1,780.75

$1780.75=\frac{5801+x}{12}\\1780.75\times 12=5801+x\\21369=5801+x\\21369-5801=x\\15568=x$

Total income of Eric for the remaining 8 months = $15568

Average income of Eric for the remaining 8 months = $\frac{15568}{8}=\$1946$

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Step-by-step explanation:

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