How do you find the arc length of a semi-circle?
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This question is incomplete, the complete question is;
An envelope company has redesigned their large envelopes.
The new designs is shown below; The missing diagram of the envelope is uploaded along this answer below.
a) Determine the area of the envelope
b) The supply paper comes in sheets that are one 130 cm x 220 cm how many envelopes can accompany make from each sheet of paper
Answer:
a) Area of the envelope is 1450 cm²
b) The company can make 19 envelopes from each of the sheet paper.
Step-by-step explanation:
Given the data in the question,
From the diagram of the envelope below;
it can be divided into 3 part
First part is the Triangle, Middle part is a rectangle and the last part is a smaller rectangle.
From the image;
First Part
Base of the Triangle is 30 cm while the height is 14 cm
so Area Of the Triangle = × base × height
= × 30 cm × 14 cm = 210 cm²
Middle Part;
Length of the middle Rectangle = 20 cm
while the breadth = ( 30cm + 1 cm + 1 cm ) = 32 cm
So Area of the Middle Rectangle = Length × Breadth
= 20 cm × 32 cm = 640 cm²
Last part;
Length of the Rectangle = 20 cm
while the breadth = 30cm
So Area of the Last Rectangle = Length × Breadth
= 20 cm × 30 cm = 600 cm²
∵ Total AREA = 210 cm² + 640 cm² + 600 cm² = 1450 cm²
Therefore, the area of the envelope is 1450 cm²
b)
given that; supply paper comes in sheets that are 130 cm by 220 cm,
how many envelopes can accompany make from each sheet of paper.
Number of enveloped that can be made = Area of Supply paper / Area of envelope
N = ( 130 cm × 220 cm ) / 1450 cm²
N = 28600 cm² / 1450 cm²
N = 19.724 ≈ 19 { We round down, else the supply paper wont be enough }
Therefore, The company can make 19 envelopes from each of the sheet paper.
Answer:
x= 11.9 (3 s.f.)
Step-by-step explanation:
Please see attached picture for full solution.
