In an equation the Left hand side must equal the right hand side
4(5y-8-2)=185-15
20y-32-8=170
20y=170+32+8
20y=210
Therefore y=10,5
When you substitute the 10,5 and solve it on the left and side it's equal to 170 which is the answer on the right hand side
Answer:
The information we need is that the angle between the sides (that is, angle TVU for triangle TVU and angle WVX for triangle WVX) need to be equal.
These angles are vertically opposite angles, because they are formed by two lines crossing, so these angles are equal.
Step-by-step explanation:
The SAS Congruence Theorem says that if two triangles have 2 equal sides and the angle between these sides are also equal, the triangles are congruent.
In this question, we know that the sides UV and VW are congruent, as V is the midpoint of UW. We also know that TV = VX, so now we have two equal sides for each triangle.
The information we need is that the angle between the sides (that is, angle TVU for triangle TVU and angle WVX for triangle WVX) need to be equal.
These angles are vertically opposite angles, because they are formed by two lines crossing, so these angles are equal.
Now we can conclude that the triangles are congruent.
You add the like terms. In this case, the like terms are -6w,+7w & 5,-4.
-6w + 7w = 1w.
5 - 4 = -1.
The coefficients (terms with variables - letters) comes firm, then the terms (numbers)
.
so the final answer is: 1w -1 :)
It’s not b or d so it’s either a or c. Hope this helped
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Answer:
we know that, Volume of cube=a³
Let volume of 1st cube be 2x with side a and other be x with side A (according to given ratio)
Step-by-step explanation:
ATQ: 2x=a³ and, x=A³
a=³√2x and, A=x
we know that, surface area of cube is 6a²
Thus, surface area of 1st cube = 6(³√2x)²
= 6³√4x²
Surface area of 2nd cube=6(x)²=6x²
Ratio of S.A=(6³√4x²)÷(6x²)
Ratio of S.A=³√4:1
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