Question

Adam is ordering pizza for a company party that he needs to have catered. Company A charges $8 for each pizza and a delivery/set-up fee of $45. Company B charges $12 for each pizza and a delivery/set-up fee of $5. Which inequality can be used to find x, the least number of pizzas that can be ordered so that the total charge for Company A is less than the total charge for Company B?

Answer 1

Answer:

Inequality is  $8x+45 < 12x+5$ and value of x>10.

Step-by-step explanation:

Given : Adam is ordering pizza for a company party that he needs to have catered.

Company A charges $8 for each pizza and a delivery/set-up fee of $45. Company B charges $12 for each pizza and a delivery/set-up fee of $5.

To find : Which inequality can be used to find x, the least number of pizzas that can be ordered so that the total charge for Company A is less than the total charge for Company B?

Solution : Let x be the number of pizza

Company A charges $8 for each pizza and a delivery/set-up fee of $45.

Total charge of Company A is $8x+45$

Company B charges $12 for each pizza and a delivery/set-up fee of $5.

Total charge of Company B is $12x+5$

The total charge for Company A is less than the total charge for Company B

i.e, Inequality form  $8x+45 < 12x+5$

$\Rightarrow 45-5< 12x-8x$

$\Rightarrow 40< 4x$

$\Rightarrow \frac{40}{4}< x$

$\Rightarrow 10< x$

or x> 10

Therefore, Inequality is   $8x+45 < 12x+5$ and value of x>10.