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Andrei [34K]
3 years ago
14

Please help with this

Mathematics
1 answer:
julsineya [31]3 years ago
5 0
Here's the work and the answer. I hope this helps.

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F(x) is a function.<br>A. True <br>B. False​
shepuryov [24]

Answer:

True.That should be the answer

4 0
3 years ago
Please help, I’ll mark brainiest
diamong [38]

The translation is 5 up and 5 to the right

8 0
4 years ago
Prove that: <img src="https://tex.z-dn.net/?f=tan20%2B4sin20%3D%5Csqrt%7B3%7D" id="TexFormula1" title="tan20+4sin20=\sqrt{3}" al
ankoles [38]

tan( 20 ) + 4 Sin( 20 ) =

( Sin( 20 ) / Cos( 20 ) ) + 4 Sin( 20 ) =

Sin( 20 ) + 4 Sin( 20 ).Cos( 20 ) / Cos( 20 ) =

Sin( 20 ) + 2 × 2 Sin(20).Cos(20)/ Cos(20) =

Sin( 20 ) + 2 × Sin( 40 ) / Cos( 20 ) =

Sin( 20 ) + 2Sin( 40 ) / Cos( 20 ) =

Sin( 20 ) + 2Cos( 50 ) / Cos ( 20 ) =

Sin( 20 ) + 2Cos( 20 + 30 ) / Cos( 20 ) =

________________________________

2 × Cos( 30 + 20 ) =

2 × [ Cos(30).Cos(20) - Sin(30).Sin(20) ] =

2 × [ √3/2 × Cos(20) - 1/2 × Sin(20) ] =

√3 Cos(20) - Sin(20)

_________________________________

Sin( 20 ) + 2Cos ( 20 + 30 ) / Cos( 20 ) =

Sin( 20 ) + √3 Cos(20) - Sin(20) / Cos(20) =

Sin(20) - Sin(20) + √3 Cos(20) / Cos(20) =

0 + √3 Cos(20) / Cos(20) =

√3 Cos(20) / Cos(20) =

Cos(20) simplifies from the numerator and denominator of fraction

√3 × 1 / 1 =

√3

And we're done ....

4 0
3 years ago
What is the coefficient of q in the sum of these two expressions? (23q – 34) and (–16q – r) NEED HELPPP
jeyben [28]

Answer:

The coefficient of q is 7

Step-by-step explanation:

The two expressions are

23q-34 and -16q-r.


The sum of the two expressions is


23q-34+-16q-r


When we group like terms the expression will be,


=23q-16q-r-34


When we  simplify the expression will now be


=7q-r-34

The coefficient of q is the constant behind q in the expression.

The coefficient of q is  therefore 7.



5 0
4 years ago
when steve woke up. his temperature was 102°F. Two hours later it was 3° lower. what was his temperature then
AlexFokin [52]
The final temperature is the sum of the initial temperature and the change in temperature. The initial temperature is 102°F. The change in temperature is -3°F.

Operation:

Tf = Ti + ΔT = 102°F + (-3°F) = (102 - 3)°F = 99°F
7 0
3 years ago
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