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faust18 [17]
3 years ago
11

There is always a 1 to 1 correspondence between the number guanines (G) and the number of cytosines (C) in a DNA molecule. The s

ame is true of the relationship between adenine (A) and thymine (T). Of course Professor Floop knows this. He analyzed a strand of DNA and determined the amounts of C and G it contained. If the molecule was 22% G, what was the percentage of A, assuming that DNA only contains G, C, A, and T
Mathematics
1 answer:
amid [387]3 years ago
4 0

Answer:

the strand contains 28% of adenine.

Step-by-step explanation:

We have only four components, and we only know one of them:

\left[\begin{array}{cc}C&?\\G&22\%\\A&?\\T&?\end{array}\right]

Cytosine has a relation 1 to 1 with G, therefore the strand must contain the same amount of C as it posses G:

\left[\begin{array}{cc}C&22\%\\G&22\%\\A&?\\T&?\end{array}\right]

Therefore:

A + T = 100\% - (C+G)

This is because the strain only contains those 4 components.

since A and T have also a 1 to 1 relation, we can state that A = T in quantity.

So:

A + A = 100\% - (C+G)

2A = 100\% - (22\%+22\%)

A = \frac{100\%-44\%}{2}

A = \frac{56%}{2}

A = 28\%

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How to reduce into simpler terms.?
Sveta_85 [38]

Answer:

The simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

Step-by-step explanation:

Here are some simple observations regarding how to reduce a fraction into simpler terms:

  • A fraction is reduced to lowest or simplest terms by finding an equivalent fraction in which the numerator and denominator are as small as possible.
  • In order to reduce a fraction to lowest or simplest terms, divide the numerator and denominator by their (GCF). Note that (GCF) is also called Greatest Common Factor .

So, lets take a sample fraction and reduce into simpler terms.

Considering the fraction

\frac{45}{100}

\mathrm{Find\:a\:common\:factor\:of\:}45\mathrm{\:and\:}100\mathrm{\:in\:order\:to\:cancel\:it\:out}

\mathrm{Greatest\:Common\:Divisor\:of\:}45,\:100:\quad 5

\mathrm{Factor\:out\:}5\mathrm{\:from\:the\:numerator\:and\:the\:denominator}

45=5\cdot \:9\mathrm{,\:\quad }100=5\cdot \:20

so

\frac{45}{100}=\frac{5\cdot \:\:9}{5\cdot \:\:20}

\mathrm{Cancel\:the\:common\:factor:}\:5

     =\frac{9}{20}

Therefore, the simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

4 0
4 years ago
Find f(4) when f(x) = 5x^2 - 5x + 7.<br><br> A) 107<br> B) 53<br> C) 67<br> D) 3
fgiga [73]
I think the answer is 67
5 0
4 years ago
Plz help! I don’t understand this
kiruha [24]

Answer:

Option B

Step-by-step explanation:

-1/2x≥4

1) Multiply both sides of the inequality by the reciprocal of -1/2: (-2)

x≤-8

Graph x≤-8 as a line. Remember that lesser negative values go to the left!

ALSO don't forget when you multiply both sides of an inequality by a negative number the inequality sign flips.

5 0
3 years ago
Unfortunately, no one buys your bracelets at a price of $10. this is a signal for you to _____. make more bracelets lower your p
tamaranim1 [39]
I would think you would lower ur price. But I wouldn't  make the price so low so that it costs the same to produce them as it does to sell them, because then there would be no profit.
3 0
4 years ago
Read 2 more answers
A random sample of 20 healthy adults was collected and their body temperatures were measured in degrees Fahrenheit. The data can
castortr0y [4]

Answer:

Step-by-step explanation:

Hello!

You need to test the hypothesis that "the average temperature for healthy adults is not equal to 98.6"

The variable of interest is

X: The body temperature of a healthy adult. (Fahrenheit)

And the parameter of interest is the population mean, μ.

The statistic hypotheses are:

H₀: μ = 98.6

H₁: μ ≠ 98.6

α:0.05

Assuming that the variable has a normal distribution you have to use a one-sample t-statistic for this test.

Attached to the answer is the data of body temperature of n=19 healthy adults. Since you didn't copy the raw data for your exercise I'll use this to answer the question.

Using the data the sample mean and standard deviation are:

X[bar]= 98.12

S= 0.69

t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~~t_{n-1}

t_{H_0}= \frac{98.12-98.6}{\frac{0.69}{\sqrt{19} } } = -3.03

This test is two-tailed, using the critical value approach, you have the rejection region divided into two tails determined by two critical values:

t_{n-1;\alpha /2}= t_{18;0.025}= -1.965

t_{n-1;1-\alpha /2}= t_{18;0.975}= 1.965

Decision rule:

If t_{H_0} ≤ -1.965 or if t_{H_0} ≥ 1.965, the decision is to reject the null hypothesis.

If -1.965 < t_{H_0} < 1.965, the decision is to not reject the null hypothesis.

The calculated statistic is less than the lower critical value, the decision is to reject the null hypothesis.

Using a significance level of 5%, there is enough evidence to reject the null hypothesis. Then you can conclude that the true mean body temperature for healthy adults is not equal to the traditional 98.6F.

I hope this helps!

7 0
4 years ago
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