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3 years ago

Which shows the rational expression written using the least common denominator?x-2/x^3

Mathematics

1 answer:

Gelneren [198K]3 years ago

6 0

Answer:

Multiply 2/3 and your number. If you have a whole number, convert it to a fraction by putting it over a denominator of 1. When multiplying fractions, calculate numerator times numerator, then denominator times denominator. For example, to find two-thirds of 18, multiply 2/3 x 18/1 to get 36/3.

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A four sided polygon is called a

Mazyrski [523]

A 4 sided polygon is a quadrilateral

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4 years ago

Read 2 more answers

Suppose that true average price of a beer at professional sporting events in the US is $6. You attend 34 events and find an aver

aniked [119]

Answer: The standard error for sample is 0.0686 .

Step-by-step explanation:

We know that the formula to find the standard error is given by :-

$S.E.=\dfrac{s}{\sqrt{n}}$

, where s = standard deviation

n= Sample size

As per given , we have

s= $0.4 and n= 34

Then , the standard error for sample is given by :-

$S.E.=\dfrac{0.4}{\sqrt{34}}=\dfrac{0.4}{5.83095189485}\\\\=0.0685994340569\approx0.0686$

Hence , the standard error for sample is 0.0686 .

5 0

4 years ago

If a 5-foot post casts an 8-foot shadow at the same time that a nearby tree casts a 48-foot shadow, how tall is the tree?

stira [4]

30 feet you multiple both numbers by 6

3 0

4 years ago

What is a polynomial with a single root at x = -1 and a double root at x = 6?

Kazeer [188]

In article <[email protected]>,
[email protected] (Hauke Reddmann) wrote:

> Let a*x**3+b*x**2+c*x+d=0 have a double and a single root.
> What's the value of the single root?

2 3
d (-9 d a + 4 d b c - c )
----------------------------------
2 2 2 2 4
6 d c a + 4 d b - 5 b c d + c

or any other expression equivalent under 

2 2 3 2 2 3
(27 d a + 4 b d - 18 c a d b - b c + 4 c a) = 0

which is the discriminant condition for the double root to occur (a being
nonzero assumed).

Maple verification:

> f:=a*x^3+b*x^2+c*x+d;
3 2
f := a x + b x + c x + d

> dis:=factor(resultant(f,diff(f,x),x));
2 2 3 2 2 3
dis := a (27 d a + 4 b d - 18 c a d b - b c + 4 c a)

>
factor(subs(x=d*(-9*d^2*a+4*d*b*c-c^3)/(6*d^2*c*a+4*d^2*b^2-5*b*c^2*d+c^4),f));

3 4 2 3 2 3 3 3 2 2 2 4
d (-27 d a + 36 d a b c - 9 d a c + 16 d b - 24 d b c + 9 d b c

6 2 2 3 2 2 3 /
- c ) (27 d a + 4 b d - 18 c a d b - b c + 4 c a) /
/

2 2 2 2 4 3
(6 d c a + 4 d b - 5 b c d + c )

> (Bonus points if it's possible to write the answer without
> using fractions, just as polynome(a,b,c,d) )

Impossible, multiplying all a,b,c,d by the same factor lambda should
preserve the solution but cannot preserve a polynomial expression.
--

4 0

3 years ago

Can someone show me the steps to solving this (Rationalizing Denominator)

Crazy boy [7]

Answer:

$\huge \purple {\frac{2 \sqrt[3]{6} + \sqrt[3]{18} }{ 6} }$

Step-by-step Explanation:

$\huge \frac{2 + \sqrt[3]{3} }{ \sqrt[3]{6} } \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )}{ \sqrt[3]{6} } \times \frac{ \sqrt[3]{6} \times \sqrt[3]{6} }{\sqrt[3]{6} \times \sqrt[3]{6}} \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )}{ \sqrt[3]{6} } \times \frac{ \sqrt[3]{6 ^{2} } }{\sqrt[3]{6^{2}} } \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )\sqrt[3]{6} }{ \sqrt[3]{6} \times \sqrt[3]{6 ^{2} }} \\ \\ = \huge \frac{(2 \sqrt[3]{6} + \sqrt[3]{3} \sqrt[3]{6} )}{ \sqrt[3]{6 ^{3} }} \\ \\ = \huge \orange{\frac{2 \sqrt[3]{6} + \sqrt[3]{18} }{ 6} }$

6 0

3 years ago