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3 years ago

The three expressions, sin-2, cos-1, and tan-1 are called _ trigonometric functions

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

3 0

Answer:

Inverse.

Step-by-step explanation:

Inverse trigonometric functions.

e. g. tan-1 x means 'the angle whose tangent is x'.

They are also called arcsin, arccos and arctan.

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The number of students who signed a petition for more after-school sports is 195, or 30% of the students at school. Terry's

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Answer:

650

Step-by-step explanation:

195

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100

and these 30 zero cut and 100 zero also cut and 3 * 195= 65 and 65 x 10 =650

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2 years ago

Helppp please it may be simple for u!

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3 years ago

The graph of f(x) was vertically translated down by a value of k to get the function g(x) = 5x + k. What is the value of k? A -7

Nadya [2.5K]

Answer:

${\boxed{\text{A. }\math{k = -7}}$

Step-by-step explanation:

The general rule for vertical translation of a function ƒ(x) ⟶ ƒ(x) + k .

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The graph of ƒ(x) was shifted from (0, 1) to (0, -6).

$\text{The graph was shifted down by seven units, so }{\boxed{\mathbf{k = -7}}$

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4 years ago

Read 2 more answers

PLEASE HELP ME!!!! I NEED THIS QUICKLY!!

zloy xaker [14]

Part A: $y=-\frac{5}{4} x+\frac{35}{2}$ is the equation of the line.

Part B: Anika worked 17.5 hours on day 0.

Part C: The setup time decreases with 1 hour and 15 min per day.

Explanation:

Part A: Let us find the equation of the line using the points (2,15) and (6,10)

The equation of the line is given by,

$y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \cdot\left(x-x_{1}\right)$

Substituting, we get,

$y-15=\frac{10-15}{6-2} (x-2)$

Simplifying, we have,

$y-15=-\frac{5}{4} (x-2)$

$y-15=-\frac{5}{4} x+\frac{5}{2}$

Subtracting both sides by 15, we get,

$y=-\frac{5}{4} x+\frac{35}{2}$

Hence, the equation of the line is $y=-\frac{5}{4} x+\frac{35}{2}$

Part B: To determine the number of hours Anika worked on day 0, let us substitute x = 0 in the equation of the line.

Thus, we get,

$y=\frac{35}{2}\\y=17.5$

Hence, Anika worked 17.5 hours on day 0.

Part C: The setup time decrease per day can be determined using the slope.

The formula for slope is given by

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting , we have,

$m=\frac{10-15}{6-2}=-\frac{5}{4}$

Converting the fraction into hours and minutes, we get,

$-\frac{5}{4}\times60=-75 min$

Since, 1 hour = 60 min

Subtracting 60 and 75 = 15 min

Thus, the setup time decreases with 1 hour and 15 min per day.

6 0

3 years ago

Divide 4 1/4 by 2.

Aleonysh [2.5K]

I’m pretty sure it’s 2 1/8

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3 years ago