Answer:
2 and 3
Step-by-step explanation:
If you nee solving it will be:
c^6(-3c^5)^2
c^6(3c^5)^2
c^6·3^2(c^5)^2
c^6·9(c^5)^2
c^6·9c^10
9c^6c^10
9c^6+10
9c^16
So the answer is:
9c^16
(9c to the power of 16)
Sorry I was late..
2^31
use the rule that states the product of the same base with different powers you add them
(a^n) times (a^m) = a^(n+m)
