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grigory [225]
3 years ago
7

Kite EFGH is inscribed in a rectangle such that F and H are midpoints and EG is parallel to the side of the rectangle.

Mathematics
2 answers:
Artemon [7]3 years ago
7 0

Answer:

The area of EFGH is always One-half of the area of the rectangle. is correct

Step-by-step explanation:

aivan3 [116]3 years ago
5 0

Answer:

"The area of EFGH is always One-half of the area of the rectangle."

Step-by-step explanation:

<em>Graph is attached.</em>

<em />

The kite consists of 2 triangle, EFG and EHG.

The area of EFG:

\frac{1}{2}*EG*h

where h is the height from F to EG

The area of EHG:

\frac{1}{2}*EG*h_1

where h_1 is the height from H to EG

We also know that h + h _1 is the width of the rectangle and EG is the length of the rectangle

Thus,

Area of Kite = \frac{1}{2}*EG*h + \frac{1}{2}*EG*h_1 = RectangleLength*RectangleWidth

Also, Area of rectangle is rectangle length * rectangle width.

Thus, area of kite is always half of that of rectangle, the third choice is right.

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