X - 26 = 57
If you were to find what 'x' was it would be 83
The greatest common factor is 5
Answer:
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Step-by-step explanation:
denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier
then
P(A)= ∑ P(Bi)*P(C) with i from 1 to 3
P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125
from the theorem of Bayes
P(Cz/A)= P(Cz∩A)/P(A)
where
P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained
P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100
therefore
P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Based on the absolute deviations and the predicted values, the sum of absolute deviations will be <u>4.8.</u>
<h3>What would be the sum of absolute deviations from predicted values?</h3>
This can be found as:
= ∑ (Observed value - Predicted value)
The observed values are given in the table and the predicted values will be calculated using y = 3.6x - 0.4.
Solving gives:
= [3 - (3.6 x 1 - 0.4)] + [7 - (3.6 x 2 - 0.4)] + [ 9 - (3.6 x 3 - 0.4)] + [14 - (3.6 x 4 - 0.4)] + [15 - (3.6 x 5 - 0.4)] + [21 - (3.6 x 6 - 0.4)] + [25 - (3.6 x 7 - 0.4)]
= 0.2 + 0.2 + 1.4 + 0 + 2.6 + 0.2 + 0.2
= 4.8
Find out more on absolute deviation at brainly.com/question/447169.
