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3 years ago

Find the greatest number which divides 615 and 963 leaving the remainder 6 in each case

1 answer:

5 0

615 - 6 = 609
963 - 6 = 957

609=3×3×29
957=3×11×29
HCF=3×29=87
The largest number that divides 615 and 963 leaving remainder 6 in both numbers is 87.

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Gabby assumed she could sell 45 boxes of cookies by Friday, but she only sold 26 boxes. What was Gabby's percent error?

Agata [3.3K]

Answer:

73.07%

Step-by-step explanation:

Given that,

Actual value of sold cookies = 26

Assumed value of sold cookies = 45

We need to find Gabby's percent error. The percentage error in a value is given by :

Error = ](Assumed value - Actual value)/Actual value]× 100

So,

$\%=\dfrac{45-26}{26}\times 100\\\\=73.07\%$

So, Gabby's percent error is equal to 73.07%.

4 0

2 years ago

X×9=y, y-70=11 , y=?

solmaris [256]

Answer:

y=81

Step-by-step explanation:

x=9 and y=81

y-70=11 (add 70 onto 11)

y=81

5 0

2 years ago

Read 2 more answers

Let g(x)= -x^2+4x+4. Find g(p). g(p)=_____

mixer [17]

Answer:

g(p)= -p^2+4p+4

Step-by-step explanation:

g(x)= -x^2+4x+4

Replace x with p

g(p)= -p^2+4p+4

8 0

3 years ago

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

Bro...help me<br><br> What is the equation of the square root function in the graph

Yuki888 [10]

Answer:

No this is not correct question for me but I am not sure what to

7 0

3 years ago