Find the greatest number which divides 615 and 963 leaving the remainder 6 in each case
1 answer:
615 - 6 = 609
963 - 6 = 957
609=3×3×29
957=3×11×29
HCF=3×29=87
The largest number that divides 615 and 963 leaving remainder 6 in both numbers is 87.
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