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steposvetlana [31]
3 years ago
14

In a certain town, the wind speed, x, in km/h on a certain day is described by two statements: If 2 times the wind speed is incr

eased by 2, the wind speed is still less than 46 km/h. Twice the wind speed minus 27 is greater than 11 km/h. Part A: Create a compound inequality to represent the wind speed range. (3 points) Part B: Can the wind speed in this town be 20 km/h? Justify your answer by solving the inequalities in Part A. (3 points) Part C: The average wind speed in another town is 23 km/h, but the actual wind speed is within 4 km/h of the average. Write and solve an inequality to find the range of wind speed in this town.
Mathematics
1 answer:
hodyreva [135]3 years ago
4 0
<span>1) if 2 times the wind speed is increased by 2, the wind speed is still less than 46 km/h.

=> 2x + 2 < 46

2) Twice the wind speed minus 27 is greater than 11 km/h.

=> 2x - 27 > 11

Part A: Create a compound inequality to represent the wind speed range. (3 points)


from 2x + 2 < 46

=> 2x < 44

=> x < 22

from 2x - 27 > 11

=> 2x > 11 + 27

=> 2x > 38

=> x > 19

The set of inequalities is

2x + 2 <46
2x - 27 > 11

The solution is x < 22 and x > 19, which is:

19 < x < 22 <----- answer

Part B: Can the wind speed in this town be 20 km/h? Justify your answer by solving the inequalities in Part A. (3 points)

Yes, the wind speed can be 20 km/h, because the solution of the inequality is the range (19,22).

Part C: The average wind speed in another town is 23 km/h, but the actual wind speed is within 4 km/h of the average. Write and solve an inequality to find the range of wind speed in this town.

x ≥ 23 - 4 => x ≥ 19

x ≤ 23 + 4=> x ≤ 27

=> 19 ≤ x ≤ 27

=> [19,27]
</span>
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Match the verbal expression (term) with its algebraic expression (definition).

Some number increased by two ⇒ b + 2

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2 years ago
7. Eduardo has $150 in savings and makes $9.75 per hour. Jennifer has $90 in savings and earns $15.25 for each
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Answer:

  a) 150-90 = h(15.25 -9.75)

  b) 10.91

Step-by-step explanation:

a) Jennifer has 150 -90 = 60 less in savings than Eduardo, but she is earning 15.25 -9.75 = 5.50 more per hour. An equation she can use to figure her hours is ...

  60 = 5.50h . . . . for h hours worked.

In 'raw' form, that might be ...

  150 -90 = (15.25 -9.75)h

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b) Solving the above equation, we get ...

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3 years ago
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A spinner with 10 equally sized slices is shown below. (3 slices are blue, 2 are yellow, and 5 are rec the probability that the
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Answer:

1/2

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5 0
2 years ago
In a chemical plant, 24 holding tanks are used for final product storage. Four tanks are selected at random and without replacem
Damm [24]

Answer:

a) P(A) = 0,4607     or   P(A) = 46,07 %

b) P(B) = 0,7120   or 71,2 %

c) P(C) = 0,2055  or P(C) = 20,55 %

Step-by-step explanation:

We will use two concepts in solving this problem.

1.- The probability of an event (A) is for definition:

P(A) = Number of favorable events/ Total number of events FE/TE

2.- If A and B are complementary events ( the sum of them is equal to 1) then:

P(A) = 1 - P(B)

a) The total number of events is:

C ( 24,4) = 24! / 4! ( 24 - 4 )!    ⇒  C ( 24,4) = 24! / 4! * 20!

C ( 24,4) = 24*23*22*21*20! / 4! * 20!  

C ( 24,4) = 24*23*22*21/4*3*2

C ( 24,4) = 24*23*22*21/4*3*2    ⇒  C ( 24,4) =  10626

TE = 10626

Splitting the group of tanks in two 6 with h-v  and 24-6 (18) without h-v

we get that total number of favorable events is the product of:

FE = 6* C ( 18, 3)  = 6 * 18! / 3!*15!  =  18*17*16*15!/15!

FE =  4896

Then P(A) ( 1 tank in the sample contains h-v material is:

P(A) = 4896/10626

P(A) = 0,4607     or   P(A) = 46,07 %

b) P(B) will be the probability of at least 1 tank contains h-v

P(B) = 1 - P ( no one tank with h-v)

Again Total number of events is 10626

The total number of favorable events for the ocurrence of P is C (18,4)

FE = C (18,4) = 18! / 14!*4! = 18*17*16*15*14!/14!*4!

FE = 18*17*16*15/4*3*2  = 3060

Then P = 3060/10626

P = 0,2879

And the probability we are looking for is

P(B) = 1 - 0,2879

P(B) = 0,7120   or 71,2 %

c) We call P(C) the probability of finding exactly 1 tank with h-v and t-i

having 4 with t-i tanks is:

reasoning the same way but now having 4 with t-i (impurities) number of favorable events is:

FE = 6*4* C(14,2) = 24 * 14!/12!*2!

FE = 24* 14*13*12! / 12!*2

FE = 24*14*13/2    ⇒  FE = 2184

And again as the TE = 10626

P(C) = 2184/ 10626

P(C) = 0,2055  or P(C) = 20,55 %

5 0
3 years ago
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