The first is C. The second is A.
Answer:
Step-by-step explanation:
Perimeter of a rectangle=(length+width)×2
Let W=x, L=2x+2
25=[(2x+2)+x]×2
25=[2x+2+x]×2
Solve for x
25/2=3x+2
25/2-2=3x
25-4/2=3x
21\2=3x=7/2=x
The value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4
<h3>Vertex Form of a quadratic expression</h3>
Given the quadratic expressions
1.5x^2+6x+......
1.5(x^2 + 4x)
Using the completing the square method
The coefficient of x = 4
Half of the coefficient = 4/2 = 2
The square of the result = 2^2 = 4
The equation is expressed as:
f(x) = 1.5(x^2+4x+ 4) - 4
f(x) = 1.5(x+2)^2 - 4
Hence the value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4
Learn more on completing the square method here: brainly.com/question/1596209
Answer:
the answer is B
Step-by-step explanation:
just did the test
31 degrees, 31 degrees, 118 degrees
Step-by-step explanation:
Step 1 :
Let x be the measure of 2 angles of the given isosceles triangle with same measure
Let y be the measure of 3rd angle
So we have x + x + y = 180
Step 2 :
Given that the measure of 3rd angle of triangle is 25° more than three times the measure of either of the other two angles
So we have , y = 3 x + 25
Step 3:
Substituting for y in the first equation we have,
x + x + 3 x + 25 = 180
=> 5 x + 25 = 180
=> 5 x = 180-25 = 155
=> x = 155/5 = 31
Hence the 2 angles of the triangle are 31 degrees.
Step 4:
we have y = 3 x + 25
=> y = 3 * 31 + 25 = 118
Hence the 3rd angle of given triangle is 118 degrees