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ruslelena [56]
2 years ago
10

A snack food manufacturer buys corn for tortilla chips from two cooperatives, one in Iowa and one in Illinois. The price per uni

t of the Iowa corn is $6.00 and the price per unit of the Illinois corn is $5.50.
a. Define variables that would tell how many units to purchase from each source.

b. Develop an objective function that would minimize the total cost.

c. The manufacturer needs at least 12,000 units of corn. The Iowa cooperative can supply up to 8000 units, and the Illinois cooperative can supply at least 6000 units. Develop constraints for these conditions.
Mathematics
1 answer:
aleksandrvk [35]2 years ago
6 0

Answer:

a. <u>x1 = No. of units to purchase from Iowa</u>

   <u>x2 = No. of units to purchase from Illinois</u>

<u></u>

b. <u>Min 6x1 + 5.5x2</u>

<u></u>

c. <u>x1 + x2 ≥ 12000</u>

   <u>x1 ≤ 8000</u>

   <u>x2 ≥ 6000</u>

Step-by-step explanation:

a. We can consider the variables x1 and x2 as:

<u>x1 = No. of units to purchase from Iowa</u>

<u>x2 = No. of units to purchase from Illinois</u>

<u></u>

b. Price per unit of Iowa corn = $6

   Price per unit of Illinois corn = $5.5

Objective function that would minimize the total cost can be written as:

<u>Min 6x1 + 5.5x2</u>

<u></u>

c. The manufacturer needs at least 12000 units of corn which means that the combined number of units from Iowa and Illinois must be greater than or equal to  12000. So, we can write:

x1 + x2 ≥ 12000

The Iowa cooperative can supply up to 8000 units which means that the value of x1 must not be greater than 8000. So, we can write:

x1 ≤ 8000

Similarly, the Illinois cooperative can supply at least 6000 units which means that the value of x2 must not be less than 6000. So, we can write:

x2 ≥ 6000.

The constraints for these conditions are:

<u>x1 + x2 ≥ 12000</u>

<u>x1 ≤ 8000</u>

<u>x2 ≥ 6000</u>

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Answer:

a) (x-2)(x-6) + (y-5)(y-11) =0\Rightarrow (x-4)^{2}+(y+3)^{2}=68\\C(4,-3) \:r=\sqrt{68} b) (a,b) (c, d) As long as (a,b) and (c,d) are the endpoints of of the diameter.

Step-by-step explanation:

a)

1) The reduced formula of the Circumference is given by:

(x-a)^{2}}+(y-b)^{2}=r^{2}

2) Let's expand the factored one into one closer to the pattern above:

x^{2}-8x+12+y^{2}+6y-55=0\Rightarrow x^{2}-8x+y^{2}+6y=43

3) Completing the square for both trinomials:

(x-4)^{2}+(y+3)^{2}=43+16+9\Rightarrow (x-4)^{2}+(y+3)^{2}=68

4) In the Reduced Formula, (x-a)^{2}}+(y-b)^{2}=r^{2},

C(a,b) \Rightarrow C(4,-3) \:the\:radius\:is\:r=\sqrt{68} \Rightarrow r=2\sqrt{17}

b) Using the previous example to show this:

When we  factor this way

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We are indeed, naming "a" and "b", the coordinates of (a, b) of the first endpoint and "b" and "d" the second endpoint as well.Id est, D (2, 5) and B (6,-11).

The radius, is \sqrt{68} \cong 8.25

So yes, the equation of the circle can be written as

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As long as (a,b) and (c,d) are the endpoints of of the diameter.

d_{AC}=d_{BC}=R

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