This question is incomplete because it was not written properly
Complete Question
A teacher gave his class two quizzes. 80% of the class passed the first quiz, but only 60% of the class passed both quizzes. What percent of those who passed the first one passed the second quiz? (2 points)
a) 20%
b) 40%
c) 60%
d) 75%
Answer:
d) 75%
Step-by-step explanation:
We would be solving this question using conditional probability.
Let us represent the percentage of those who passed the first quiz as A = 80%
and
Those who passed the first quiz as B = unknown
Those who passed the first and second quiz as A and B = 60%
The formula for conditional probability is given as
P(B|A) = P(A and B) / P(A)
Where,
P(B|A) = the percent of those who passed the first one passed the second
Hence,
P(B|A) = 60/80
= 0.75
In percent form, 0.75 × 100 = 75%
Therefore, from the calculations above, 75% of those who passed the first quiz to also passed the second quiz.
(5x-7) + (3x-4) + (2x-6)
5x-7+3x-4+2x-6
10x-17.
The answer could be (6,3) or ( -3,8)
Answer:
The answer to your question is: b = 6√3
Step-by-step explanation:
Here we have a right triangle, so we can use the Pythagorean theorem to solve it.
c² = a² + b²
c = 9 + 3 = 12 units
a = 6 units
b = ?
Substitution
12² = 6² + b²
b² = 144 - 36
b² = 108
b = 10.4 units or we need to find the prime factors of 108
108 2
54 2
27 3
9 3
3 3
1 108 = 2² 3²3
b = √ 2² 3²3
b = 6√3
