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2 years ago

Please help 15 points and brainliest!

Mathematics

1 answer:

Umnica [9.8K]2 years ago

3 0

C because the proportions are equal and multiplied by 4/4

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For right triangle ABC, find the sine ratio of angle θ.

Ket [755]

The sine ratio of angle θ is 4/5 because sin is the ratio to opposite to the hypotenuse.

<h3>What is a right-angle triangle?</h3>

It is a triangle in which one of the angles is 90 degrees and the other two are sharp angles. The sides of a right-angled triangle are known as the hypotenuse, perpendicular, and base.

We have a right angle triangle showing in a picture.

As we know, the sin is the ratio to opposite to the hypotenuse.

Sinθ = 4/5

Thus, the sine ratio of angle θ is 4/5 because sin is the ratio to opposite to the hypotenuse.

Learn more about the right angle triangle here:

brainly.com/question/3770177

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8 0

2 years ago

Find volume of sphere in cubic yards whose radius is 5 yard<br><br> Use pi = 3.14

enyata [817]

Answer:

523.333 cubic yards

Step-by-step explanation:

The formula for the volume of a sphere is $\frac{4}{3}\pi r^{3}$ where $r$ is the radius.

The radius of the given sphere is $r=5$ yards and $\pi =3.14$ .

Therefore, we can substitute in the radius and solve:

$V_{sphere}= \frac{4}{3}\*\times3.14\times 5^{3} =523.333$ cubic yards

4 0

1 year ago

Read 2 more answers

If a pen and a pencil cost 1.10$ but the pen cost is 1$ more than pencil

Stella [2.4K]

Answer:

The pencil cost $0.05 and the pen cost $1.05.

Step-by-step explanation:

Let, the price of the pencil is $ .

Given that the pen costs a dollar more than the pencil,

So, the price of the pen=$+1.

Therefore, ++1=1.10

, 2+1=1.10

, 2=1.10–1

, 2=0.10

, =0.10/2

, =0.05

The pencil cost $0.05 and the pen cost $1.05.

4 0

2 years ago

OPTIONS<br> Pack of 24 for $1.68<br> UNIT PRICE<br> $<br> per<br> Pack of 12 for $1.08<br> $<br> per

notsponge [240]

Pack of 6 for $0.34 there u go

3 0

3 years ago

Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that

aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

$A\cap B=$ {HH}

$B\cap C$ ={HH}

$A\cap C$ ={HH}

P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

$P(A)=\frac{2}{4}=\frac{1}{2}$

Number of favorable cases to event B=2

Number of favorable cases to event C=2

$P(B)=\frac{2}{4}=\frac{1}{2}$

$P(C)=\frac{2}{4}=\frac{1}{2}$

If the two events A and B are independent then

$P(A)\cdot P(B)=P(A\cap B)$

$P(A\cap)=\frac{1}{4}$

$P(B\cap C)=\frac{1}{4}$

$P(A\cap C)=\frac{1}{4}$

$P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}$

$P(B)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(B)=P(A\cap B)$

Therefore, A and B are independent

$P(B)\cdot P(C)=P(B\cap C)$

Therefore, B and C are independent

$P(A\cap C)=P(A)\cdot P(C)$

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

6 0

3 years ago