Answer:
the initial height of ball when the player releases it
Step-by-step explanation:
A basketball player shoots a free throw in a game. The quadratic expression models the height of the ball, in feet, where t is the time, in seconds.
y= -16t^2 + 25t+7
Given equation is in the form of
y= -16x^2 + V t + h
Where V represents the initial velocity and h represents the initial height of the ball
Now we compare our equation with the general equation
We have 7 in the place of h
So , 7 is the initial height of the ball
Answer is 7 is the initial height of ball when the player releases it
Answer:
17
Step-by-step explanation:
8 + 36/4 = 8 + 9 = 17
Class 1= 6+x
class 2 = x
total= 50
so you need to find the x
50=6+x+x
50=2x+6
50-6=2x
44=2x
22=x
22+6
28 is the larger class
Answer:
C. 8, H. 6x^2+43x+55
Step-by-step explanation:
You're looking for a value that will make x-2=6, since you add exponents. So W^8/W^-2 is equal to 1/W^6. Since 8-2=6.
A= length * width
(2x+11)(3x+5), foil it out by taking 2x(3x+5), then 11(3x+5).
6x^2+10x+33x+55, combine like terms
6x^2+43x+55
