Answer:
a + m = 2+ a
Step-by-step explanation:
We don't know the amount of apple granola and the amount of the maple granola. So we just set an equation.
It would be the last option, (5, -4)
Answer:
Step-by-step explanation:
perimeter of the figure = perimeter of the rectangle + perimeter of the semicircle
= 2(l+B) +
r
= 2( 10+8) + 3.14 × 5
= 36 + 15.7
= 51.7
= 100 ( rounding off to nearest hundredth )
hope this helps
plz mark it as brailiest!!!!!!
It’s the last answer because the slope equals 1 which basically equals just x. And the y intercept is -5
Answer:
1963.2 pounds (lbs.)
Step-by-step explanation:
Things to understand before solving:
- - <u>Normal Probability Distribution</u>
- The z-score formula can be used to solve normal distribution problems. In a set with mean ц and standard deviation б, the z-score of a measure X is given by:

The Z-score reflects how far the measure deviates from the mean. After determining the Z-score, we examine the z-score table to determine the p-value associated with this z-score. This p-value represents the likelihood that the measure's value is less than X, or the percentile of X. Subtracting 1 from the p-value yields the likelihood that the measure's value is larger than X.
- - <u>Central Limit Theorem</u>
- The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean ц and standard deviation б , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean ц and standard deviation

As long as n is more than 30, the Central Limit Theorem may be applied to a skewed variable. A specific kind of steel cable has an average breaking strength of 2000 pounds, with a standard variation of 100 pounds.
This means, ц = 2000 and б = 100.
A random sample of 20 cables is chosen and tested.
This means that n = 20, 
Determine the sample mean that will exclude the top 95 percent of all size 20 samples drawn from the population.
This is the 100-95th percentile, or X when Z has a p-value of 0.05, or X when Z = -1.645. So 
- By the Central Limit Theorem


<h3>Answer:</h3>
The sample mean that will cut off the top 95% of all size 20 samples obtained from the population is 1963.2 pounds.