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PolarNik [594]
1 year ago
8

Please help and answer has an exponent

Mathematics
1 answer:
Len [333]1 year ago
4 0
2^6 (or two to the sixth power) is equal to 4^3, which equals out to 64.
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Bags of maple granola cost $2 more than apple granola
Brilliant_brown [7]

Answer:

a + m = 2+ a

Step-by-step explanation:

We don't know the amount of apple granola and the amount of the maple granola. So we just set an equation.

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3 years ago
3x + 2y = 7
Lady bird [3.3K]
It would be the last option, (5, -4)
4 0
2 years ago
Find the perimeter of this figure to the nearest hundredth use 3.14 to approximate pi P=?ft
blagie [28]

Answer:

Step-by-step explanation:

perimeter of the figure = perimeter of the rectangle + perimeter of the semicircle

= 2(l+B) + \pi r

= 2( 10+8) + 3.14 × 5

= 36 + 15.7

= 51.7

= 100 ( rounding off to nearest hundredth )

hope this helps

plz mark it as brailiest!!!!!!

4 0
3 years ago
Read 2 more answers
Help me quys plz, which one is it
torisob [31]
It’s the last answer because the slope equals 1 which basically equals just x. And the y intercept is -5
7 0
3 years ago
The average breaking strength of a certain brand of steel cable is 2000 pounds, with a standard deviation of 100 pounds. A sampl
Westkost [7]

Answer:

1963.2 pounds (lbs.)

Step-by-step explanation:

Things to understand before solving:

  • - <u>Normal Probability Distribution</u>
  1. The z-score formula can be used to solve normal distribution problems. In a set with mean ц and standard deviation б, the z-score of a measure X is given by: Z=\frac{X-u}{a}

The Z-score reflects how far the measure deviates from the mean. After determining the Z-score, we examine the z-score table to determine the p-value associated with this z-score. This p-value represents the likelihood that the measure's value is less than X, or the percentile of X. Subtracting 1 from the p-value yields the likelihood that the measure's value is larger than X.

  • - <u>Central Limit Theorem</u>
  1. The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean ц and standard deviation б , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean ц  and standard deviation s=\frac{a}{\sqrt{n} }

As long as n is more than 30, the Central Limit Theorem may be applied to a skewed variable. A specific kind of steel cable has an average breaking strength of 2000 pounds, with a standard variation of 100 pounds.

This means, ц  = 2000 and б = 100.

A random sample of 20 cables is chosen and tested.

This means that n = 20, s=\frac{100}{\sqrt{120} } =22.361

Determine the sample mean that will exclude the top 95 percent of all size 20 samples drawn from the population.

This is the 100-95th percentile, or X when Z has a p-value of 0.05, or X when Z = -1.645. So Z=\frac{X-u}{a}

  • By the Central Limit Theorem

Z=\frac{X-u}{a} \\-1.645=\frac{X-2000}{22.361} \\X-2000=-1.645*22.361

X =1963.2

<h3>Answer:</h3>

The sample mean that will cut off the top 95% of all size 20 samples obtained from the population is 1963.2 pounds.

3 0
2 years ago
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