Answer: 4.05 mol O2, 15.36 mol H2O
Explanation:
I can answer each question individually if you post them individually.
2a. 3.24 mol NH3 * (5 mol O2 / 4 mol NH3) = 4.05 mol O2
2b. 12.8 mol O2 ( 6mol H2O/ 5 mol O2) = 15.36 mol H2O
Essentially what I did was dimensional analysis. Multiplying in a way that the units cancel out so the only thing remains is what each question asks for.
Medications for skin , and medication for babies
PV = nRT
⇒P1/T1 = P2/T2
⇒500/300 = 100/T2
⇒ T2 = 100×300/500 = 60K
Answer is D
Ok boomer..................
[H_{3}O^{+}] = 0.00770 M
The equilibrium equation representing the dissociation of 

Given [H_{3}O^{+}] = 0.00770 M
Let the initial concentration of acid be x and change y
So y =
=
= 0.00770 M



0.00257 x - 0.00001979 = 0.00005929
x = 0.031 M
Therefore, initial concentration of the weak acid is <u>0.031 M</u>