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alexgriva [62]
1 year ago
7

You work in a museum that has a huge, beautiful stamed-glass window: Each gamell dints the light a different coice. Recenty up a

table m front of the wmdiow: Plant 1 is im fiont of a biue stained glass, Plant 2 is in font of a purgie you tall the museum directur to move so it doesnit became maicurshed?You work in a museum that has a huge, beautiful, stained-glass window. Each panel tints the light a different color. Recently a new exhibit showcasing plants from around the world has set up a table in front of the window. Plant 1 is in front of a blue stained glass, Plant 2 is in front of a purple stained glass, and Plant 3 is in front of a green stained glass. Which plant should you tell the museum director to move so it doesn't become malnourished?
A. Plant 2
B. Plant 1
C. Plant 3
D. All three plants
Chemistry
1 answer:
borishaifa [10]1 year ago
3 0

The plant that should be moved here to protect from malnourishment is plant 3. The correct option is C.

<h3>What is visible spectrum?</h3>

The visible light spectrum is the portion of the electromagnetic spectrum that can be seen by the human eye. Simply put, this range of wavelengths is known as visible light.

The visible spectrum, also known as the optical spectrum, is the portion of the electromagnetic spectrum whose radiation consists of photons capable of sensitizing a normal person's human eye. The corresponding visible light radiation range is identified.

That being said, plant 3 is situated in front of a green stained glass window.

Plants have chlorophyll pigment that reflects back green light, making green light less effective for photosynthesis and causing them to die as quickly as if they were kept in the dark.

Thus, the correct option is C.

For more details regarding visible spectrum, visit:

brainly.com/question/12807557

#SPJ1

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Answer:

0.1066 hours

Explanation:

A common pesticide degrades in a first-order process with a rate constant (k) of 6.5 1/hours. We can calculate its half-life (t1/2), that is, the times that it takes for its concentration to be halved, using the following expression.

t1/2 = ln2/k

t1/2 = ln2/6.5 h⁻¹

t1/2 = 0.1066 h

The half-life of the pesticide is 0.1066 hours.

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Answer:

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