The most characteristic property of the noble gases is that they

How many grams of carbon are present in 45.0g of CCl4

pentagon [3]

Molar Mass of CCl4= 12+4(35.5)=154 g/mol g Carbon= 45.0g/(154 g/mol)=0.292 mole

6 0

3 years ago

Tonya had a mixture of sand, salt, iron particles, and pebbles. What processes should be used to separate the substances in the

marusya05 [52]

Explanation:

Put the pan into a water-containing dish and mix well. Now use a strainer to transfer the solution into another jar. The salt should disappear in it.

And using a tube with a filtrate, transfer the salts that has sand into another bottle with a filtrate. Therefore the sand is split. Eventually, when all the water vaporizes and the salt stays in the bottle, leave the extra solvent and heat it.

3 0

3 years ago

The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively.

user100 [1]

Answer:

c 43.38 g

Explanation:

The reaction between MnO2 and HCl can be represented by the following balanced equation:

MnO2 + HCl ---> Cl2 + MnCl2 + H2O

From the balanced equation, the theoretically required molar ratio of MnO2 to HCl is 1:1, therefore the yields would have been expected to be equal.

For the fact that HCl gives a higher yield (65.02g) than MnO2 (60.25g) according to the problem statement, HCl should be in excess, while the limiting reagent should be MnO2 .

Thus, the theoretical yield of Cl2 will be 60.25 g.

By definition, the percentage yield is given by

% Yield = (Actual Yield) / (Theoretical Yield),

This can be simplified to

Actual Yield = % Yield * Theoretical Yield

Plugging in the given values we have

Actual Yield = 72% * 60.25 = 43.38 g

5 0

3 years ago

You wash dishes for a chemistry laboratory to make extra money for laundry. You earn 12 dollars/hour, and each shift lasts 75 mi

nadezda [96]

Answer:

A)You must work 2 shifts to wash 10 loads of laundry

B)You can wash 15 loads pf laundry if you work for 3 shifts

C) each shift will pay for 3.75 loads of laundry if the cost per load rises to 16 quarters

Explanation:

Given:

amount earned = 12 dollars/hour

Duration for one shift = 75 minutes

Amount needed for Laundry = 12 quarters/load.

A. How many shifts must you work if you wish to wash 10 loads of laundry

To wash 10 loads, you will be requiring

=> $10 \times 12 \text{quarters}$

=> 120 quarters

1 quarter = 0.25 dollars---------------------------------(1)

120 quarters

= $120 \times 0.25 \text{ dollars}$

= 30 dollars

You need 30 dollars for washing 10 loads

In one hour i,e 60 minutes you earn= 12 dollars

In one minute the amount earned will be

$= \frac {12}{60}$

= 0.2 dollar-------------------------------------------------------(2)

Now to earn 30 dollars you have to work for

= $30 \times 0.2$ minutes

= 150 minutes

Thus the number of shifts will be

= $\frac{150}{75}$

= 2 shifts

B. How many loads of laundry can you wash if you work 3 shifts

We Know that 1 shift = 75 minutes

So 3 shifts = $75 \times 3$ = 225 minutes

From (2),

In 1 minute = 0.2 dollars is earned

So in 225 minutes = 225 \ times 0.2 = 45 dollar is earned

45 dollar = $45 \times 4$ = 180 quarters

You can wash 1 load with 12 quarters

With 180 quarters you can wash = $\frac{180}{12}$ = 15 loads

C. How many loads of laundry will each shift pay for if the cost per load rises to 16 quarters

Cost per load = 16 quarters

From (1)

16 quarters = $0.25 \times 16$ = 4 dollars per load

From (2) In 1 shift the amount earned will be

=> $75 \times 0.2$

=15 dollars

With 4 dollars you can wash 1 load

So with 15 dollars = $\frac{15}{4}$ = 3.75 loads

4 0

3 years ago

3) In the reaction below, how many grams of carbon dioxide are produced when iron III

Yanka [14]

<h3>Answer:</h3>

132.03 g

<h3>Explanation:</h3>

<u>We are given;</u>

The equation for the reaction as;

Fe₂O₃ + 3CO → 2Fe + 3CO₂

Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
Mass of CO as 84 grams

We are required to calculate the mass of CO₂ that will produced.

<h3>Step 1: Calculate the number of moles of CO</h3>

Moles = Mass ÷ Molar mass

Molar mass of CO = 28.01 g/mol

Therefore;

Moles of CO = 84 g ÷ 28.01 g/mol

= 2.9989 moles

= 3.0 moles

<h3>Step 2: Calculate the number of moles of CO₂</h3>

From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂

Therefore; the mole ratio of CO to CO₂ is 1 : 1
Hence; Moles of CO = Moles of CO₂

Moles of CO₂ = 3.0 Moles

But; mass = Moles × molar mass

Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol

= 132.03 g

Hence, the mass of CO₂ produced from the reaction is 132.03 g

3 0

4 years ago