Solve the equation a/a^2-16+2/a-4=2/a+4

Hello.

Move −25-25 to the right side of the equation by subtracting −25-25 from both sides of the equation.x2=25x2=25

Take the square root of both sides of the equation to eliminate the exponent on the left side.

The complete solution is the result of both the positive and negative portions of the solution.

Simplify the right side of the equation.

Rewrite 2525 as 5252.

Pull terms out from under the radical, assuming positive real numbers.The complete solution is the result of both the positive and negative portions of the solution.

The complete solution is the result of both the positive and negative portions of the solution.

Answer: x=5,−5

Have a nice day

6 0

3 years ago

Read 2 more answers

Can anybody teach me how to solve this pls

wel

Answer is 10 and 170, complementary angles are 90°, while supplementary angles are 180 in total, if angle A is 80 then you subtract 90 by 80 and you get 10, so that is angle B, So then you are asked what is angle C. Which is part of the supplementary angle so you take the 10° that you got from B and then you subtract 180 by the 10, And thats how you get 170 and that's how you know that C is 170 (hope this explanation helps)

3 0

3 years ago

Can I get some help please? Thanks!

quester [9]

An ellipse (oval shape) is expressed by the following equation:

$\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2}=1$ where h is the x coordinate of the center and k is the y coordinate of the center. Furthermore, a is the horizontal distance from the center, and b is the vertical distance from the center. Lastly, c is the distance from the center to one of the foci (they are spaced apart equally).

We can find the foci by using $a^2 - b^2 = c^2$

36 - 11 = $c^2$

$c = \sqrt{25} = 5$

Since the k value in this case is 0, the y value of both foci are 0. Also, since h and k are both 0, we know the center of the ellipse is at the origin.

So the foci are (-5, 0) and (5, 0)

Hope this helps :)

3 0

3 years ago