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Ne4ueva [31]
3 years ago
15

Miguel buys a car for $12,999.The tax is 6% what is the total price of the car

Mathematics
2 answers:
Brrunno [24]3 years ago
5 0

Answer:

13778.94

Step-by-step explanation:

did it on my calculator

Nastasia [14]3 years ago
4 0
799.94 i know cuz im big brain
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suppose the temperature outside is dropping 2.5 degrees each hour how much will the temperature change in 6 hours​
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15 degrees

Step-by-step explanation:

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8 0
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jayce runs 2 1/2 miles on monday. Each day after that, he runs the same 1 1/3 mile route every morning. His goal is to run at le
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3 0
2 years ago
A survey of 200 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take
Lina20 [59]

Answer:

The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>P</em> is:

CI=p\pm z_{\alpha/2}\sqrt{\frac{p(1- p)}{n}}

The information provided is:

<em>x</em> = number of students who responded as"yes" = 70

<em>n</em> = sample size = 200

Confidence level = 95%

The formula to compute the sample proportion is:

p=\frac{x}{n}

The R codes for the construction of the 95% confidence interval is:

> x=70

> n=200

> p=x/n

> p

[1] 0.35

> s=sqrt((p*(1-p))/n)

> s

[1] 0.03372684

> E=qnorm(0.975)*s

> lower=p-E

> upper=p+E

> lower

[1] 0.2838966

> upper

[1] 0.4161034

Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

7 0
4 years ago
Read 2 more answers
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