A) 2/3 divided by 5/1
= 2/3 X 1/5
= 2/15 of the book
B) 14X5=70
1/3
2/3
3/3
70+35= 105 pages
Answer :
<h3>
<u>
=1048576 ways </u>
a student can answer the questions on the test if the student answers every question.</h3>
Step-by-step explanation:
Given that a multiple-choice test contains 10 questions and there are 4 possible answers for each question.
∴ Answers=4 options for each question.
<h3>
To find how many ways a student can answer the given questions on the test if the student answers every question :</h3>
Solving this by product rule
Product rule :
<u>If one event can occur in m ways and a second event occur in n ways, the number of ways of two events can occur in sequence is then m.n</u>
From the given the event of choosing the answer of each question having 4 options is given by
The 1st event of picking the answer of the 1st question=4 ,
2nd event of picking the answer of the 2nd question=4 ,
3rd event of picking the answer of the 3rd question=4
,....,
10th event of picking the answer of the 10th question=4.
It can be written as by using the product rule



<h3>∴ there are 1048576 ways a student can answer the questions on the test if the student answers every question.</h3>
I'm presuming that the 'large cube' is made from 8 cubes the same size as the 8 cubes in the long row. They both have the same volume, the only difference between them is that they are arranged in a different order. Hope this helps. If not feel free to ask again and give more information.
Answer:
a) To earn C he needs at least 68 and less than 98
b) No, he couldn't make it.
Step-by-step explanation:
I. His avg value is (382 + x)/6
I pick a random number and that gave
(68 => to reach 75) and (98 => to reach 80)
So that makes he needs at least 68 and less than 98
II. The reason why he cannot make it is
if 100 is 100%
= (100 + 382)/6
= 80.33 That's impossible to reach 90
Hope that help :)
The missing justification in the proof is
<span>B) Substitution property of equality
The expression for sin</span>² x and cos² x is substituted to the other side of the equation. Since sin x = a/c, then sin² x = a²/c². Similarly, since cos x = b/c, then cos² x = b²/c². Adding to two results to the third statement.