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-BARSIC- [3]
3 years ago
9

A car traveled 462 miles per tankful of gasoline on the highway and 336 miles per tankful of gasoline in the city. If the car tr

aveled 6 fewer miles per gallon in the city than on the highway, how many miles per gallon did the car travel in the city?

Mathematics
2 answers:
aivan3 [116]3 years ago
6 0

Answer:

16 miles per gallon

Step-by-step explanation:

Please kindly check the attached file for explanation.

vampirchik [111]3 years ago
6 0

Answer:

The car traveled 16 miles per gallon in the city

Step-by-step explanation:

Speed in highway = a miles per gallon

Speed in city = b miles per gallon

The car covers a miles with 1 gallon of fuel in the highway

It will cover 462 miles with 462/a gallons of fuel in the highway

The car covers b miles with 1 gallon of fuel in the city

It will cover 336 miles with 336/b gallons of fuel in the city

The car traveled 6 fewer miles per gallon in the city than on the highway

b = a - 6

Since the speed does not change with the fuel capacity of the car

462/a = 336/b

But b = a -6

462/a = 336/(a-6)

462(a-6) = 336a

462a - 2772 = 336a

462a - 336a = 2772

126a = 2772

a = 2772/126

a = 22 miles per gallon

The car travel 22 miles per gallon in the highway

In the city, b = a -6

b = 22 -6

b = 16 miles per gallon

The car traveled 16 miles per gallon in the city

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Eugene and three of his friends went out to eat. They decided to split the bill evenly. Each person paid $11. What was the total
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Answer:

Step-by-step explanation:

Je calcule la facture totale

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2 years ago
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<span>An alternative equivalent versions are:

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5 0
3 years ago
Read 2 more answers
Calculate the average time the car took to reach each checkpoint. Record the average time in Table D of your Student Guide. The
zhuklara [117]

The average time the car took to reach each checkpoint are:

  • 2.07
  • 3.16
  • 4.11
  • 4.92

<h3>Average time</h3>

Given:

Time  interval

1              2      3           4

2.02    3.17   4.12    4.93

2.05    3.07  3.98   4.81

2.15    3.25  4.23    5.01

Hence:

First quarter checkpoint

Average time= (2.02 + 2.05 + 2.15) / 3

Average time=6.22/3

Average time= 2.07s

Second quarter checkpoint

Average time= (3.17 +3.07 + 3.25) / 3

Average time=9.49/3

Average time = 3.16 s

Third quarter check point

Average time= (4.12 + 3.98 + 4.23) / 3

Average time=12.33/3

Average time= 4.11 s

Fourth quarter check point

Average time = (4.93 + 4.81 + 5.01) / 3

Average time=14.75/3

Average time= 4.917 s

Average time=4.92s (Approximately)

Therefore the average time the car took to reach each checkpoint are: 2.07, 3.16, 4.11, 4.92.

Learn more about average time here:brainly.com/question/19136062

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Jlenok [28]
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V = 1/3(3.14 * 3.75^2) * 3.5

V = 1/3(44.16) * 3.5

V = 1/3*154.56

V = 51.5 cm^3 of feed
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3 years ago
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