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3 years ago

10

How does scientific theory compare to scientific law

1 answer:

Troyanec [42]3 years ago

6 0

N general, a scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory.

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The dopamine molecule has an intermediate hydrophobicity. Edit the dopamine molecule so that it is more hydrophobic.

yulyashka [42]

You should edit the dopamine molecule by tampering with its polar groups. Polar groups affect chemical's physical properties including hydrophobicity.

5 0

4 years ago

How many grams are in .11 moles of Cu

kodGreya [7K]

Answer:

m= 6.9905 = 7 g

Explanation:

The formula is m= M.n

m= mass (g), M= Molar mass (g/mole), n= moles (moles)

Molar mass of Cu is 63.55

=) m= 63.55*0.11

m= 6.9905 = 7 g

5 0

3 years ago

What should be the mole fraction of O2 in the gas mixture the diver breathes in order to have the same partial pressure of oxyge

Nutka1998 [239]

The question is incomplete, here is the complete question:

A scuba diver is at a depth of 355 m, where the pressure is 36.5 atm.

What should be the mole fraction of $O_2$ in the gas mixture the diver breathes in order to have the same partial pressure of oxygen in his lungs as he would at sea level? Note that the mole fraction of oxygen at sea level is 0.209.

<u>Answer:</u> The mole fraction of oxygen in the gas mixture is 0.00573

<u>Explanation:</u>

To calculate the partial pressure, we use the equation given by Raoult's law, which is:

$p_{A}=p_T\times \chi_{A}$ ........(1)

where,

$p_A$ = partial pressure of oxygen at sea level = ?

$p_T$ = total pressure at sea level = 1.00 atm

$\chi_A$ = mole fraction of oxygen at sea level = 0.209

Putting values in equation 1, we get:

$p_{O_2}=1.00atm\times 0.209\\\\p_{O_2}=0.209atm$

As, partial pressure of the oxygen in the diver's lungs is equal to the partial pressure of oxygen at sea level

We are given:

$p_T=36.5atm\\p_{O_2}=0.209atm$

Putting values in equation 1, we get:

$0.209atm=36.5atm\times \chi_{O_2}\\\\\chi_{O_2}=\frac{0.209}{36.5}=0.00573$

Hence, the mole fraction of oxygen in the gas mixture is 0.00573

3 0

3 years ago

What kind of hydrocarbon is this? C-C-C-C-C-C-C-C-OH <br><br> Please help ASAP

Mice21 [21]

Answer:

1-Octanol

Explanation:

Count the amount of carbon atoms in the chain. Nomenclature includes the position of the largest functional group position in the molecule.

In this case the carbon chain has 8 carbon atoms and one hydroxide functional group (OH)

1 (hydroxide is listed first in the carbon chain) - Oct(8 carbons) + anol (Alkanol hydrocarbon with a hydroxide group, use anol suffix )

= 1 - Octanol

7 0

3 years ago

A balloon originally had a volume of 4.39 L at 44C and a pressure of 729 torr to what temperature must the balloon be cooled

VMariaS [17]

The new temperature : 11.56 °C

<h3>Further explanation </h3>

Boyle's law and Gay Lussac's law

$\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}$

P1 = initial gas pressure (N/m² or Pa)

V1 = initial gas volume (m³)

P2 = final gas pressure

V2 = final gas volume

T1 = initial gas temperature (K)

T2 = final gas temperature

V₁=4.39 L

T₁=44+273=317 K

P₁ = 729 torr = 0,959211 atm

V₂=3.78 L

P₂= 1 atm

$\tt \dfrac{0.959211\times 4.39}{317}=\dfrac{1\times 3.78}{T_2}\\\\T_2=\dfrac{1\times 3.78\times 317}{0.959211\times 4.39}\\\\T_2=284.559~K=11.56~C$

3 0

3 years ago