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Georgia [21]
3 years ago
8

Which of the following is a term used to describe the shallow location near the shore where water covers the continent?

Chemistry
2 answers:
Bingel [31]3 years ago
4 0
Continental shelf

is the edge of a continent that lies under the ocean. It extends from the coastline of a continent to a drop-off point called the shelf break. Even though they are underwater, continental shelves are part of the continent. The formation of continental shelves were once dry land, the most recent ice age, much of the frozen huge masses of ice glaciers.
tatuchka [14]3 years ago
4 0
The answer would be option B "Continental shelf." Continental shelf are known as shallow location near the shore where water covers the continent, its like a shore or a border that covers part of a country like a line. So, a term used to describe the shallow location near the shore where water covers the continent would be a <span>Continental shelf!

Hope this helps!
</span>
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2 NH3 + 3 CuO →3 Cu + N₂ + 3 H₂O
Tatiana [17]

40.1g of nitrogen gas is produced.

The equation given is

2 NH₃ + 3 CuO →3 Cu + N₂ + 3 H₂O

This equation is already balanced.

When 3 moles of CuO are consumed, 1 mole of nitrogen gas is produced.

We get 1 mole of nitrogen from 3 moles of copper oxide.

We need to find the number of moles of nitrogen gas produced when 4.3 moles of copper oxide are consumed.

4.3/3 x 1 = 1.433 mols

  • 1.433 mols of nitrogen gas are produced
  • The molar mass of nitrogen gas is 14+14 = 28g
  • The amount of nitrogen gas produced in grams is 28x1.433 = 40.1g

40.1g of nitrogen gas can be made when 4.3 moles of CuO are consumed.

Learn more about molarity here:

brainly.com/question/24305514

#SPJ10

5 0
2 years ago
Why is glass brittle
WITCHER [35]
Glass doesn't contain planes of atoms that can slip past each other, so there is no way to relieve stress. It has many microscopic cracks that act as seeds for fracture. It’s molecular structure is composed of tetrahedral crystals so it ruptured easily under stress
6 0
3 years ago
A spring-fed stream forms a pond that contains watercress plants, minnows, and crayfish. The pond receives 5 hours of direct sun
Snowcat [4.5K]

Answer:

The pond water

8 0
3 years ago
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An analytical chemist is titrating of a solution of ethylamine with a solution of . The of ethylamine is . Calculate the pH of t
Elenna [48]

Answer:

pH=11.

Explanation:

Hello!

In this case, since the data is not given, it is possible to use a similar problem like:

"An analytical chemist is titrating 185.0 mL of a 0.7500 M solution of ethylamine(C2HNH2) with a 0.4800 M solution of HNO3.ThepK,of ethylamine is 3.19. Calculate the pH of the base solution after the chemist has added 114.4 mL of the HNO3 solution to it"

Thus, for the reaction:

C_2H_5NH_2+H^+\rightleftharpoons C_2H_5NH_4^+

Tt is possible to compute the remaining moles of ethylamine via the following subtraction:

n_{ethylamine}=0.1850L*0.7500mol/L=0.1365mol\\\\n_{acid}=0.1144L*0.4800mol/L=0.0549mol\\\\n_{ethylamine}^{remaining}=0.1365mol-0.0549mol=0.0816mol

Thus, the concentration of ethylamine in solution is:

[ethylamine]=\frac{0.0816mol}{0.1850L+0.1144L}=0.2725M

Now, we can also infer that some salt is formed, and has the following concentration:

[salt]=\frac{0.0549mol}{0.1850L+0.1144L}=0.1834M

Therefore, we can use the Henderson-Hasselbach equation to compute the resulting pOH first:

pOH=pKb+log(\frac{[salt]}{[base]} )\\\\pOH=3.19+log(\frac{0.1834M}{0.2725M})\\\\pOH=3.0

Finally, the pH turns out to be:

pH=14-pOH=14-3\\\\pH=11

NOTE: keep in mind that if you have different values, you can just change them and follow the very same process here.

Best regards!

4 0
3 years ago
30 POINTS PLEASE HELP ASAP
lina2011 [118]

Hello!

We have the following data:

f (radiation frequency) = 3.0*10^{19}\:Hz

v (speed of light) = 3.0*10^8\:m/s

λ (wavelength) = ? (in m)

Let's find the wavelength, let's see:

f = \dfrac{v}{\lambda}

3.0*10^{19} = \dfrac{3.0*10^8}{\lambda}

\lambda = \dfrac{3.0*10^8}{3.0*10^{19}}

\boxed{\boxed{\lambda = 1*10^{-11}\:m}}\Longleftarrow(wavelenght)\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

4 0
3 years ago
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